C= chair cost
t= table cost
Create two equations with the given information. Solve for one variable in equation one. Substitute that answer in equation two. Then you can solve for the needed information.
3c+2t=$18
5c+6t=$48
3c+2t=18
Subtract 2c from both sides
3c=18-2t
Divide both sides by 3
c=(18-2t)/3
Substitute the value for c in equation two:
5c+6t=$48
5((18-2t)/3)+6t=48
(90-10t)/3+6t=48
Multiply everything by 3 to eliminate fraction
(3)((90-10t)/3)+(3)(6t)=(3)(48)
90-10t+18t=144
90+8t=144
Subtract 90 from both sides
8t=54
Divide both sides by 8
t=$6.75 cost for table
Substitute the t value to solve for c:
3c+2t=18
3c+2(6.75)=18
3c+13.50=18
3c=4.50
c=$1.50 chair cost
Check:
5c+6t=$48
5(1.50)+6(6.75)=48
7.50+40.50=48
48=48
Hope this helps! :) If it does, please mark as brainliest.
Sides are always equal. Pretty sure
In the step after -6x+10=4x+20, he moved the terms incorrectly. you have to add 6x to both sides so it would be 10=4x+6x+20 which simplifies to 10=10x+20. subtract 20 from both sides to get -10=10x. divide both sides by 10. the answer is x=-1
Answer:
Four times his sister's age would be 4b. his age is two years less, so we need to subtract 2.
put together, this is 4b - 2.
x = 4
First you combine like terms:
8 + 4x = 24
Then solve:
4x = 24 - 8
4x = 16
x = 16/4
x = 4
