Let x = first integer y = second integer z = third integer First equation: x + y + z = 194 Second equation: x + y = z + 80 Third equation: z = x - 45
Let's find the values of x, y and z. Substitute 3rd eq to 1st eq: x + y + x - 45 = 194 2x + y = 45 + 194 y = -2x + 239
Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x x + (-2x + 239) = (x - 45) + 80 x - 2x - x = -45 + 80 - 239 -2x = -204 x = -204/-2 x = 102
