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HACTEHA [7]
3 years ago
13

Suzie paid a total of $324 dollar sign, 324 for x tickets to a rock festival.

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
6 0

Find the ticket unit cost:  divide the total paid, $324, by the number of tickets, x.  Then the form of the unit cost is

$324

--------- .

   x

This question is highly unusual in that you write "x" as the number of tickets sold, instead of a specific number of tickets.  Supposing that you'd sold 100 tickets for $324, then the unit cost would be, much more typically, a numeric ratio:

$324

----------------- = $3.24/ticket

100 tickets

Radda [10]3 years ago
6 0

Answer:

Cost of each ticket = The amount paid divided by the number of tickets x

= \frac{324}{x}

The expression = \frac{324}{x}

Step-by-step explanation:

Given: Suzie paid a total of $324 dollar sign, 324 for x tickets to a rock festival.

To find the cost of each ticket, we need to divide "the total amount by the number of tickets."

The expression that Suzie to find the cost each ticket = \frac{324}{x}, where "x" represents the number of ticket.

Cost of each ticket = The amount paid divided by the number of tickets x

= \frac{324}{x}

For instance, Suzie paid a total of $324 for 100 tickets.

The cost of each ticket = \frac{324}{100} = $3.24

If we know the number of tickets, we can find the cost of each ticket by dividing $324 by the number of tickets.

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Suppose that the researchers wanted to estimate the mean reaction time to within 6 msec with 95% confidence. Using the sample st
Lisa [10]

Answer:

a) The 95% confidence interval would be given by (509.592;550.308)  

b) n=523 rounded up to the nearest integer  

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=530 represent the sample mean for the sample  

\mu population mean

s=70 represent the sample standard deviation  

n=48 represent the sample size (variable of interest)  

Confidence =95% or 0.995

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

The degrees of freedom are df=n-1=48-1=47

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,47)".And we see that z_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

530-2.01\frac{70}{\sqrt{48}}=509.692  

530+2.01\frac{70}{\sqrt{48}}=550.308  

So on this case the 95% confidence interval would be given by (509.592;550.308)  

Part b

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (a)  

Assuming that \hat \sigma =s

And on this case we have that ME =6msec, and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (b)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (b) we got:  

n=(\frac{1.96(70)}{6})^2 =522.88 \approx 523  

So the answer for this case would be n=523 rounded up to the nearest integer  

3 0
3 years ago
Please Answer the 27the question I will mark you as the brainlest
kondor19780726 [428]

Answer:

Step-by-step explanation:

1) we have to find the area of the cut out portion

Since both circles in one side makes up the side 28cm

The diameter of each circle is 14cm

radius = diameter / 2

r = 7cm

Area of a circle = πr²

A = 22/7 × 7²

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Therefore the area of the remaining portion will be

Area of the square - total area of the circles

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The area of the remaining part is 168 cm²

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Answer:

See explanation!

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