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4 years ago

draw the graph of equation X + 2 Y equal to one also find points where line cuts x and y axis pls help me fast

Mathematics

1 answer:

chubhunter [2.5K]4 years ago

7 0

Answer:

x-Intercept: 1

y-Intercept: $\frac{1}{2}$

Step-by-step explanation:

Step 1: Rearrange the equation x+2y=1 into y=mx+b

2y = -x + 1

$y=-\frac{1}{2}x +\frac{1}{2}$

Step 2: Find x and y intercept

We know the y intercept is at 'b' which is $\frac{1}{2}$

We know the x intercept is when y = 0 so we set y = 0 and solve for 'x'

$(0)=-\frac{1}{2}x +\frac{1}{2}\\-\frac{1}{2}=-\frac{1}{2}x \\\frac{-\frac{1}{2}}{-\frac{1}{2}} = -\frac{-\frac{1}{2}}{-\frac{1}{2}}x\\1=x$

So we know when y = 0 x is equal to 1

Therefore the x intercept is 1 and the y intercept is $\frac{1}{2}$

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3 years ago

Ned,Tony,Matt and juan are palyung basketball. Ned scores 2p+3 points more than Ned, Matt scored teice as many points as Tony, a

horsena [70]

Ned scored 2p+3. Tony scored 3 points more than Ned, so Tony scored 3+2p+3, or 2p+6. Matt scored twice as many points as Tony, so Matt scored 2(2p+6), or 4p+12. Juan scored 8 fewer points than Ned, so Juan scored 2p+3-8, or 2p-5. To simplify, we add these four values. 2p + 3 2p + 6 4p + 12 2p - 5 This equals 10p + 16.

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3 years ago

Which equation represents a line which is perpendicular to the line y = -x + 8?

natima [27]

Two lines are perpendicular between each other if their slopes fulfills the following property

$m_1m_2=-1$

where m1 and m2 represents the slopes of line 1 an 2, respectively.

To find the slope of a line we can write it in the form slope-intercept form

$y=mx+b$

Our original line is

$y=-\frac{1}{8}x+8$

Then its slope is

$m_1=-\frac{1}{8}$

Now we have to find the slope of the second line. Using the first property,

$\begin{gathered} m_1m_2=-1_{} \\ -\frac{1}{8}m_2=-1_{} \\ m_2=(-1)(-8) \\ m_2=8 \end{gathered}$

Then the second line has to have a slope of 8.

The options given to us are:

$\begin{gathered} x+8y=8 \\ x-8y=-56 \\ 8x+y=5 \\ y-8x=4 \end{gathered}$

Then we have to determine which of these options have a slope of 8. To do that we write them in the slope-intercept form:

$\begin{gathered} x+8y=8\rightarrow y=-\frac{1}{8}x+1 \\ x-8y=-56\rightarrow y=\frac{1}{8}x+7 \\ 8x+y=5\rightarrow y=-8x+5 \\ y-8x=4\rightarrow y=8x+4 \end{gathered}$

Once we have the options in the right form, we note that the only one of them that has a slope of 8 is the last one.

Then the line perpendicular to the original one is