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7nadin3 [17]
3 years ago
14

draw the graph of equation X + 2 Y equal to one also find points where line cuts x and y axis pls help me fast

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
7 0

Answer:

x-Intercept: 1

y-Intercept: \frac{1}{2}

Step-by-step explanation:

Step 1: Rearrange the equation x+2y=1 into y=mx+b

2y = -x + 1

y=-\frac{1}{2}x +\frac{1}{2}

Step 2: Find x and y intercept

We know the y intercept is at 'b' which is \frac{1}{2}

We know the x intercept is when y = 0 so we set y = 0 and solve for 'x'

(0)=-\frac{1}{2}x +\frac{1}{2}\\-\frac{1}{2}=-\frac{1}{2}x \\\frac{-\frac{1}{2}}{-\frac{1}{2}} = -\frac{-\frac{1}{2}}{-\frac{1}{2}}x\\1=x

So we know when y = 0 x is equal to 1

Therefore the x intercept is 1 and the y intercept is \frac{1}{2}

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Answer:

Step-by-step explanation:

-4m + 5 = -15

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-4m = -20

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andrew-mc [135]

The remainder from the division of the algebraic equation is -53/8.

<h3>What is the remainder of the algebraic expression?</h3>

The remainder of the algebraic expression can be determined by using the long division method.

Given that:
\mathbf{f(x) = \dfrac{x^3 - 6x^2 + 3x - 1}{2x-3}}

where:

  • The divisor = 2x -3

Using the long division method, we have:

\mathbf{= \dfrac{x^2}{2} +\dfrac{-\dfrac{9x^2}{2}+3x -1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} +\dfrac{-\dfrac{-15x}{4}-1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}+\dfrac{-\dfrac{53}{8} }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}-\dfrac{53 }{8(2x-3)}}

Therefore, we can conclude that the remainder is -53/8.

Learn more about the division of algebraic equations here:

brainly.com/question/4541471

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What is the value of the missing angle??
Mice21 [21]

Answer:

39°

Step-by-step explanation:

51° +? = 90°

? = 90° - 51°

? = 39°

Hope it helps you in your learning process.

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