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7nadin3 [17]
3 years ago
14

draw the graph of equation X + 2 Y equal to one also find points where line cuts x and y axis pls help me fast

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
7 0

Answer:

x-Intercept: 1

y-Intercept: \frac{1}{2}

Step-by-step explanation:

Step 1: Rearrange the equation x+2y=1 into y=mx+b

2y = -x + 1

y=-\frac{1}{2}x +\frac{1}{2}

Step 2: Find x and y intercept

We know the y intercept is at 'b' which is \frac{1}{2}

We know the x intercept is when y = 0 so we set y = 0 and solve for 'x'

(0)=-\frac{1}{2}x +\frac{1}{2}\\-\frac{1}{2}=-\frac{1}{2}x \\\frac{-\frac{1}{2}}{-\frac{1}{2}} = -\frac{-\frac{1}{2}}{-\frac{1}{2}}x\\1=x

So we know when y = 0 x is equal to 1

Therefore the x intercept is 1 and the y intercept is \frac{1}{2}

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3 years ago
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Colt1911 [192]

Answer:

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Step-by-step explanation:

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2 years ago
For an angle θ, tan(θ) is a negative number. Which quadrants might θ be in?
Klio2033 [76]

So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.  

4 0
2 years ago
Read 2 more answers
Find the compound interest on 800 at 5% per annum for 2 years.​
Ludmilka [50]

Answer:

C = 82

Step-by-step explanation:

Given

R = 5\% -- Rate

P = 800 -- Principal

N = 2 -- Time

Required

Determine the compound interest

First, we calculate the Amount (A)

A = P(1 + R)^N

A = 800*(1 + 5\%)^2

Express % as decimal

A = 800*(1 + 0.05)^2

A = 800*(1.05)^2

A = 882

The compound interest (C) is then calculated as:

C = A -P i.e. Amount - Principal

C = 882 - 800

C = 82

7 0
2 years ago
Write out the following proportions in words. a. 7 :28 = 2 : 8 b. 3⁄1 = 18⁄6 c. 9 : 72 = 2 : 16 d. 81⁄9 = 45⁄5
Lerok [7]
1) Proportion a.

7 : 28 = 2 : 8

That means that the ratio 7 / 28 is equal to the ratio 2 : 8. 

You can verify the equality by simplifying to the simplest form:

     7 : 28 = 1 / 4 simplest form
     2 : 8 = 1 / 4 simplest form, then the proportion is right.

In words that is 7 is to 28 as 1 is to 4 ← answer


2) Proportion b.<span>. 3⁄1 = 18⁄6
</span><span>
</span><span>
</span><span>In words: 3 is to q as 18 is to 6 ← answer
</span><span>
</span><span>
</span><span>You can verify the proportion by simplifiying the second fraction:
</span><span>
</span><span>
</span><span>     18 / 6 = [18 / 6] / [ 6 / 6] = 3 / 1
</span><span>
</span><span>
</span><span>3) Proportion c. 9 : 72 = 2 : 16
</span><span>
</span><span>
</span><span>In words: 9 is to 72 as 2 is to 16 ← answer
</span><span>
</span><span>
</span><span>Proove the proportion:
</span><span>
</span><span>
</span><span>     9 / 72 = 1 / 8
</span><span>
</span><span>
</span><span>     2 / 16 = 1 / 8
</span><span>
</span><span>
</span><span>4) Proportion d. 81⁄9 = 45⁄5</span>

In words: 81 is to 9 as 45 is to 5 ← answer


Proove it: 
      81 / 9 = 9
      45 / 9 = 9
8 0
3 years ago
Read 2 more answers
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