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BaLLatris [955]
4 years ago
8

When electricity flows through water, the water molecules split into molecules of hydrogen and oxygen gas. How many oxygen (O2)

molecules are produced from the splitting of two molecules of water (H2O) if the balanced equation for the reaction is as follows? 2H2O 2H2 + O2 A. 4 B. 3 C. 2 D. 1
Chemistry
1 answer:
mel-nik [20]4 years ago
5 0

The  number  of  O2 ( oxygen)   molecules  that are produced  from splitting of two molecules  of water is 1  molecule  of oxygen ( answer D)


Explanation

A molecule   -  is a group of two or more  atoms  held together  by a chemical bond.

In  the  reaction of splitting  of  2   molecules  of  H2O  yield 1  molecule  of O2.


  • 1  molecule of O2  is made up  of two atoms of  Oxygen  held  by  double  covalent bond.  
  • The two  oxygen atom  form molecule  by sharing  two valence electrons.
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Hexose category and ketohexose category

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7 0
3 years ago
A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.692 kg of water
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Answer:

494.49 g of NaCl.

Explanation:

Data obtained from the question include the following:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mass of NaCl =.?

Next, we shall determine the number of mole of NaCl in the solution.

Molality is simply defined as the mole of solute per unit kilogram of solvent. Mathematically, it is expressed as

Molality = mole of solute /Kg of solvent

With the above formula, we can obtain the number of mole NaCl in the solution as follow:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mole of NaCl =..?

Molality = mole of solute /Kg of solvent

3.140 = mole of NaCl /2.692

Cross multiply

Mole of NaCl = 3.140 x 2.692

Mole of NaCl = 8.45288 moles

Finally, we shall covert 8.45288 moles of NaCl to grams. This can be obtained as follow:

Mole of NaCl = 8.45288 moles

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Mole = mass /Molar mass

8.45288 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 8.45288 × 58.5

Mass of NaCl = 494.49 g.

Therefore, 494.49 g of NaCl are present in the solution.

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