Answer:
D
Step-by-step explanation:
Δ CED and Δ CAB are similar thus the ratios of corresponding sides are equal, that is
=
, substitute values
=
=
( cross- multiply )
12x = 156 - x ( add x to both sides )
13x = 156 ( divide both sides by 13 )
x = 12
Thus
AC = 156 - x = 156 - 12 = 144 → D
Answer:
6.18% of the class has an exam score of A- or higher.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
What percentage of the class has an exam score of A- or higher (defined as at least 90)?
This is 1 subtracted by the pvalue of Z when X = 90. So
has a pvalue of 0.9382
1 - 0.9382 = 0.0618
6.18% of the class has an exam score of A- or higher.