For f(x)=x^5-x^3 x what is the equation of the tangent line at x=3?
1 answer:
F(x) = x^5 - x^3 + x f'(x) = 5x^4 - 3x^2 + 1 f(3) = (3)^5 - (3)^3 + 3 = 243 - 27 + 3 = 219 f'(3) = 5(3)^4 - 3(3)^2 + 1 = 5(81) - 3(9) + 1 = 405 - 27 + 1 = 379 Let the required equation of the tangent line be y = mx + c; where y = 219, m = 379, x = 3 219 = 379(3) + c = 1,137 c = 219 - 1,137 = -918 Therefore, required equation is y = 379x - 918
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<em><u>Hence , Proved</u></em> .</h2>
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<u>Hope it helps !</u> </h2>
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