We have a fraction with the unknown in the denominator, review how to treat unknowns in the denominator as a refresher for this exercise:
<span>(2/3) - (1/x + 6) = 2
</span>(2/3) - (1 + 6x)/x = <span>2
</span>(2/3) - 2 = (1 + 6x)/x
2/3 - 6/3 = (1 + <span>6x)/x
-4/3 = </span>(1 + <span>6x)/x
-4x = 3</span>(1 + <span>6x)
</span><span>-4x = 3 + 18x
</span>22x = -3
x = -3/22
Based on the calculations on this parallelogram, the correct equations are:
- n = 10
- CF = 59
- FE = 42
<h3>The properties of a
parallelogram.</h3>
Based on the image of the parallelogram shown in the image attached below, we can logically deduce that the opposite sides of this parallelogram are all equal. Thus, we have:
Side DE = Side CF
6n - 1 = 5n + 9
6n - 5n = 9 + 1
n = 10.
From Side CF, we have:
CF = 5n + 9
CF = 5(10) + 9
CF = 59.
For the measure of side FE, we have
FE = 4n + 2
FE = 4(10) + 2
FE = 42.
Read more on parallelogram here: brainly.com/question/16743544
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Complete Question:
Figure CDEF is a parallelogram.
Parallelogram C D E F is shown. The length of F C is 6 n minus 1, the length of C D is 4 n + 2, and the length of D E is 5 n + 9.
Which equations are correct? Select three options.
n = 10
n = 7
CF = 59
FE = 42
CD = 30
Answer:
The answer to your question is below
Step-by-step explanation:
Functions
f(x) = 12x f⁻¹(x) = 2x
a) f⁻¹(-2) = 2(-2)
f⁻¹(-2) = -4
b) f(-4) = 12x
f(-4) = 12(-4)
f(-4) = -48
c) f(f⁻¹(-2)) =
f(f⁻¹(x)) = 12(2x) = 24x
f(f⁻¹(-2)) = 24(-2) = -48
I think your functions are wrong they must be f(x) = 1/2x f⁻¹(x) = 2x
a) f⁻¹(-2) = 2(-2)
= -4
b) f(-4) = 1/2(-4)
= -2
c) f(f⁻¹(x)) = 1/2(2x)
= x
f(f⁻¹(-2)) = -2
Given:$75
25 hours
Painting USA : Fixed cost: $75 ; Variable Cost: $25x
Total Cost = 75 + 25(25) = 75 + 625 = 700
Upscale Home Painting: No Fixed Cost ; Variable Cost : $40x
Total Cost = 40(25) = 1,000
The most cost effective company will be Painting USA whose charge will amount to $700.
Answer:
7 : 1
Step-by-step explanation:
Paul's car goes 40 kilometers on 7 tanks.
Distance : Tanks
49 : 7
Fuel efficiency means the distance traveled by the car in one tank.
Therefore, we will reduce the ratio by dividing both sides by 7.
Distance : Tanks
: 
7 : 1
Therefore, car's fuel efficiency is 7 kilometers in one tank or the ratio between Distance traveled and fuel tanks is 7 : 1.