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GuDViN [60]
3 years ago
10

Chunking is a good strategy for completing large assignments because it makes the work

Computers and Technology
2 answers:
Bess [88]3 years ago
8 0

Answer:

ExChunking is a good strategy for completing large assignments because it makes the work

less boring.

more thorough.

less difficult.

more manageable.planation:

Explanation: less difficult (C)

miv72 [106K]3 years ago
4 0

Answer:

umm it d i think

Explanation:

the comments above where crazy and concerning its just one test question

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Zohan uses the following analogy to describe a concept of object-oriented programming. A button can have many uses. When it is p
Vika [28.1K]

Answer:

Polymorphism

Explanation:

You can have a basic button class that gets inherited by other classes.

class Button {

function pushButton(){}

}

class ElevatorButton extends Button{};

class BigRedButton extends Button{};

With these new classes, they inherit from the basic button class. They can decide what happens when the method pushButton() is called.

You don't need to worry about what pushButton() actually does, you can just call it if the object is of the type "Button" and you can expect it to work.

4 0
2 years ago
Write code that declares a variable named minutes, which holds minutes worked on a job,
Mamont248 [21]

The code that carried out the functions indicated above is stated below. It is not be noted that the code is written in C#

<h3>What is C#</h3>

C# is a type-safe, object-oriented programming language. It is pronounced "see sharp"

<h3>What is the code for the above task?</h3>

Using System;            

public class HoursAndMinutes

{

   public static void Main()

   {

      // declaring minutes variable and assigning 197 as given in question

       int minutes = 197;

     // outputing the total minutes , hours

       Console.WriteLine("{0} minutes is {1} hours and {2} minutes.", minutes, minutes/60, minutes%60);

   }

}

// OUT

Learn more about C#:
brainly.com/question/20211782
#SPJ1

8 0
2 years ago
Roger wants to give semantic meaning to the contact information, which is at the bottom of the web page. To do this he will use
Elden [556K]

Answer:

Parent

Explanation:

HTML is an acronym for hypertext markup language and it is a standard programming language which is used for designing, developing and creating web pages.

Generally, all HTML documents are divided into two (2) main parts; body and head. The head contains information such as version of HTML, title of a page, metadata, link to custom favicons and CSS etc. The body of a HTML document contains the contents or informations that a web page displays.

In this scenario, Roger wants to give semantic meaning (an element conveying informations about the type of content contained within an opening and closing tag) to a contact information placed at the bottom of a webpage. Thus, in order to do this, he should use a footer element as a parent of the contact information and as such all instance variables that have been used or declared in the footer class (superclass) would be present in its contact information (subclass object).

4 0
3 years ago
1. The following programs require using arrays. For each, the input comes from standard input and consists of N real numbers bet
Mamont248 [21]

Answer:

import java.util.*;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.Arrays;

class GFG

{

  // Function for calculating mean

  public static double findMean(double a[], int n)

  {

      int sum = 0;

      for (int i = 0; i < n; i++)

          sum += a[i];

 

      return (double)sum / (double)n;

  }

  // Function for calculating median

  public static double findMedian(double a[], int n)

  {

      // First we sort the array

      Arrays.sort(a);

      // check for even case

      if (n % 2 != 0)

      return (double)a[n / 2];

 

      return (double)(a[(n - 1) / 2] + a[n / 2]) / 2.0;

  }

  public static double findMode(double a[], int n)

{

// The output array b[] will

// have sorted array

//int []b = new int[n];

 

// variable to store max of

// input array which will

// to have size of count array

double max = Arrays.stream(a).max().getAsDouble();

 

// auxiliary(count) array to

// store count. Initialize

// count array as 0. Size

// of count array will be

// equal to (max + 1).

double t = max + 1;

double[] count = new double[(int)t];

for (int i = 0; i < t; i++)

{

count[i] = 0;

}

 

// Store count of each element

// of input array

for (int i = 0; i < n; i++)

{

count[(int)(10*a[i])]++;

}

 

// mode is the index with maximum count

double mode = 0;

double k = count[0];

for (int i = 1; i < t; i++)

{

if (count[i] > k)

{

k = count[i];

mode = i;

}

}

return mode;

}

public static double findSmallest(double [] A, int total){

Arrays.sort(A);

return A[0];

}

 

public static void printAboveAvg(double arr[], int n)

{

 

// Find average

double avg = 0;

for (int i = 0; i < n; i++)

avg += arr[i];

avg = avg / n;

 

// Print elements greater than average

for (int i = 0; i < n; i++)

if (arr[i] > avg)

System.out.print(arr[i] + " ");

System.out.println();

}

 

public static void printrand(double [] A, int n){

Arrays.sort(A);

for(int i=0;i<n;i++){

System.out.print(A[0]+"/t");

}

System.out.println();

}

 

public static void printHist(double [] arr, int n) {

 

for (double i = 1.0; i >= 0; i-=0.1) {

System.out.print(i+" | ");

for (int j = 0; j < n; j++) {

 

// if array of element is greater

// then array it print x

if (arr[j] >= i)

System.out.print("x");

 

// else print blank spaces

else

System.out.print(" ");

}

System.out.println();

}

// print last line denoted by ----

for(int l = 0; l < (n + 3); l++){    

System.out.print("---");

}

 

System.out.println();

System.out.print(" ");

 

for (int k = 0; k < n; k++) {

System.out.print(arr[k]+" ");

}

}

  // Driver program

  public static void main(String args[]) throws IOException

  {

      //Enter data using BufferReader

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

double [] A = new double[100];

int i=0;

System.out.println("Enter the numbers(0.0-1.0) /n Enter 9 if u have entered the numbers. /n");

do

{

A[i++]=Double.parseDouble(br.readLine());

}while(A[i-1]==9);

      i--;

      System.out.println("Average = " + findMean(A,i) );

      System.out.println("Median = " + findMedian(A,i));

      System.out.println("Element that occured most frequently = " + findMode(A,i));

      System.out.println("number closest to 0.0 =" + findSmallest(A,i));

      System.out.println("Numbers that are greater than the average are follows:");

      printAboveAvg(A,i);

      System.out.println("Numbers in random order are as follows:");

      printrand(A,i);

      System.out.println("Histogram is bellow:");

      printHist(A,i);

  }

}

Explanation:

3 0
3 years ago
Unscramble the words <br><br> A: ESUOM RETUPOC <br><br> B: KSID EVIRD
Mrrafil [7]
A. Mouse coputer
B. Disk drive
5 0
3 years ago
Read 2 more answers
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