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ehidna [41]
3 years ago
7

The area of a rectangular garden is 18z+24 square feet. What are the possible dimensions of the garden?

Mathematics
1 answer:
Lelechka [254]3 years ago
7 0

Given:

The area of the rectangular garden is 18z+24 sq ft.

To find the possible dimensions of the garden.

Formula

The area of the rectangular garden is

A = lb

where,

l be the length of the rectangle

b be the width.

Let us take l and b be the length and width of the given rectangular park respectively.

Now,

According to the problem,

lb = 18z+24

or, lb = 6(3z+4)

We can determine that,

l = 6 and b = 3z+4 or vice versa.

Hence,

The possible length and width of the rectangular garden is 6 and (3z+4) respectively.

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Help pls fast
Andrews [41]

Answer:

32.40cm²

Step-by-step explanation:

Given the parallelogram ABCD ;

side AB is always Parallel to CD, hence ;

AB = CD = 7.2cm

Perpendicular from C on AB is the height of the parallelogram = 4.5cm

Area of a parallelogram : base * height

Area of a parallelogram = length base * height

Area of a parallelogram = 7.2 cm * 4.5cm

Area of parallelogram = 32.40cm²

6 0
3 years ago
Plz answer this i need help!!!!!<br><br><br> The options are Multiply and Divide
Gelneren [198K]

Answer:

you multiply the circumference by the radius squared

Ex.) (c= circumference)

c=3.14x2r

3 0
3 years ago
Which sentence represents the inequality -2b + 7 &gt; 27.5?<br> Help PLEASE!
AVprozaik [17]
-2b + 7 > 27.5
- 2b > 27.5 - 7
- 2b > 20.5
b < - 10.25

7 0
3 years ago
Read 2 more answers
What is the best estimate for the percent equivalent to 3/8?
Nimfa-mama [501]
37.5% i believe! i’m not reallt sure if this is correct; but i believe it is. hope this helps!
5 0
3 years ago
Read 2 more answers
Use the data in the table to answer the question. Citations are "speeding tickets." You may fill in the table to help you answer
Vikentia [17]

Answer:

Linear approximation is given by: y = \frac{x}{5}+2

Step-by-step explanation:

We are given the following information in the question:

Number of citations:      5      7.5      10      15       20

 Outputs Residuals:       3       6       10       5          6

We have to find the linear approximation of the data that passes through the points (5, 3) and (20, 6).

Linear approximation is given by:

The equation of line is given by:

(y-y_1) = \displaystyle\frac{y_2-y_2}{x_2-x_1}(x-x_1)

where, (x_1,y_1), (x_2.y_2) is the point through which the line passes.

The equation of line is:

(y-3) = \displaystyle\frac{6-3}{20-5}(x-5)\\\\15(y-3)= 3(x-5)\\15y = 3x-15+45\\15y = 3x + 30\\y = \frac{x}{5}+2

The above equation is the required linear approximation.

8 0
3 years ago
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