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bazaltina [42]
3 years ago
5

What are the intercepts of

Mathematics
2 answers:
ad-work [718]3 years ago
8 0
My answer is D
first: type this code
then : press Calc ...

VARVARA [1.3K]3 years ago
4 0

  Answer:

Option (d) is correct.

Intercept of equation 2x + 3y - 6z = 30 is (15,0,0) ,(0,10,0) and (0,0,-5)

Step-by-step explanation:

given : The equation  2x + 3y - 6z = 30

We have to find the intercept.

Intercept are the point where equations cut the x- axis, y- axis and z- axis.

Thus, at x- axis

y and z both are zero .

So, put y = z = 0

we get,

2x + 3(0) - 6(0) = 30

2x = 30

x = 15

at y- axis

x and z both are zero .

So, put x = z = 0

we get,

2(0) + 3y - 6(0) = 30

3y = 30

y = 10

at z- axis

y and x both are zero .

So, put y = x = 0

we get,

2(0)+ 3(0) - 6z = 30

-6z = 30

z= -5

Thus, intercept of equation 2x + 3y - 6z = 30 is (15,0,0) ,(0,10,0) and (0,0,-5)

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What is y-2=-3x(x-7) written in standard form?
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8 0
3 years ago
Write -12 2/3 as an improper fraction
miv72 [106K]

Answer:

-38/3

Step-by-step explanation:

At first, you times 12 and 3, which is 36

Then you do 36+2, which is 38

Don't forget the negative sign!!!!

So it is -38/3

Hope it helped!~❤️

8 0
4 years ago
HELP PLS FOR BRAINLIEST!
igomit [66]

Answer:

Electric force = 8.20x10⁻⁸ N

Gravitational force = 3.61x10⁻⁴⁷ N

Step-by-step explanation:

1. The electric force can be found using the following equation:

F_{e} = \frac{Kq_{e}q_{p}}{d^{2}}

Where:

K: is the Coulomb's constant = 9x10⁹ N.m²/C²      

q_{p}: is the charge of the proton = 1.6x10⁻¹⁹ C

q_{e}: is the charge of the electron = -1.6x10⁻¹⁹ C

d: is the distance = 5.3x10⁻¹¹ m

Hence, the magnitude of the electric force is:

|F_{e}| = \frac{9\cdot 10^{9} N.m^{2}/C^{2}*(-1.6\cdot 10^{-19} C)*1.6 \cdot 10^{-19} C}{(5.3 \cdot 10^{-11} m)^{2}} = 8.20 \cdot 10^{-8} N                

2. The gravitational force can be calculated as follows:

F_{g} = \frac{Gm_{e}m_{p}}{d^{2}}

Where:

m_{e}: is the electron's mass = 9.1x10⁻³¹ kg

m_{p}: is the proton's mass = 1.67x10⁻²⁷ kg

G: is the gravitational constant = 6.67x10⁻¹¹ N.m²/kg²

Therefore, the gravitational force is:

F_{g} = \frac{6.67 \cdot 10^{-11} N.m^{2}/kg^{2}*9.1 \cdot 10^{-31} kg*1.67 \cdot 10^{-27} kg}{(5.3 \cdot 10^{-11} m)^{2}} = 3.61 \cdot 10^{-47} N

As we can see, the gravitational force is much less than the electric force.

I hope it helps you!                                                      

5 0
3 years ago
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