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Margaret [11]
4 years ago
15

Nicole used 3/8 of her ribbon to wrap a present if she used 6 feet of ribbon for the present how much ribbon did Nicole have at

first
Mathematics
1 answer:
11111nata11111 [884]4 years ago
3 0
To solve this, put the numbers into a ratio/fraction that you can cross multiply with. 
\frac{3}{8}= \frac{6}{x}
You are trying to find x, so cross multiply. 
3x=48
divide 48 by 3
x=16

16 feet of ribbon
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Porfavor ayúdame es para hoy ​
konstantin123 [22]
Answer: 25cm


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3 0
3 years ago
The graphs of y-2x = 1, 4x + y = 7, and 2y - x= -4 contain the sides of triangle. Find the coordinates of the vertices of the tr
Darina [25.2K]

Answer:

i think the right answer is b

6 0
4 years ago
Alim buys 2 t-shirts for $9.50 each, a 3-pack of socks for $7.95, and a pair of shoes for $7.95 and a pair of shoes for $49.95.
Usimov [2.4K]
First, I add all of my prices together.
$9.50(2)+$7.95+$7.95+$49.95= $84.85
Change 6% to a decimal = .06
Then multiply: 84.85 x .06 =  $5.09
$5.09 is the sales tax
$84.85 + $5.09 = $89.94

Answer: $89.94
I hope this helps :)
3 0
4 years ago
Translate: "The product of 8 and a number, b, is taken away from 24"
goblinko [34]
24-8b
24-(8*b)
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7 0
3 years ago
The range of y = - 32x ^ 2 + 90x + 3
mariarad [96]

Given:

The given function is:

y=-32x^2+90x+3

To find:

The range of the given function.

Solution:

We have,

y=-32x^2+90x+3

It is a quadratic function because the highest power of the variable x is 2.

Here, the leading coefficient is -32 which is negative. So, the graph of the given function is a downward parabola.

If a quadratic function is f(x)=ax^2+bx+c, then the vertex of the quadratic function is:

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

In the given function, a=-32,b=90,c=3.

\dfrac{-b}{2a}=\dfrac{-90}{2(-32)}

\dfrac{-b}{2a}=\dfrac{-90}{-64}

\dfrac{-b}{2a}=\dfrac{45}{32}

The value of the given function at x=\dfrac{45}{32} is:

y=-32(\dfrac{45}{32})^2+90(\dfrac{45}{32})+3

y=\dfrac{2121}{32}

The vertex of the given downward parabola is \left(\dfrac{45}{32},\dfrac{2121}{32}\right). It means the maximum value of the function is y=\dfrac{2121}{32}. So,

Range=\left\{y|y\leq \dfrac{2121}{32}\right\}

Range=\left(-\infty, \dfrac{2121}{32}\right ]

Therefore, the range of the given function is \left (-\infty, \dfrac{2121}{32}\right ].

8 0
3 years ago
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