How many centigrams are equal to 9.95 milligrams

For geometry:(<br><br> will give brainist to the correct answer!!!

Over [174]

Answer:

y = ⅔x - 5

Step-by-step explanation:

The line that passes through (-3, -7) will have the same slope (m) as the line, 2x - 3y = 24. This is because if two lines that are parallel to each other would have the same slope.

Rewrite 2x - 3y = 24, in the slope-intercept form, y = mx + b.

Thus:

2x - 3y = 24, rewritten would give us y = ⅔x - 8.

The slope of the line, 2x - 3y = 24, is ⅔.

Thus, the slope of the line that is parallel to 2x - 3y = 24, is also ⅔.

To find the equation, substitute a = -3, b = -7, and m = ⅔ into y - b = m(x - a).

Thus:

y + 7 = ⅔(x + 3)

Rewrite to make the equation in slope-intercept form.

Thus:

y + 7 = ⅔(x + 3)

3(y + 7) = 2(x + 3) ---› multiplication property of equality

3y + 21 = 2x + 6 ----› distributive property

3y = 2x + 6 - 21 ----› subtraction property of equality

3y = 2x - 15

y = ⅔x - 5 (division property of equality)

7 0

3 years ago

In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.

Hitman42 [59]

$\longmapsto$ The value of "x" is 5.

$\large\underline{\sf{Solution-}}$

Given that,

A trapezium ABCD in which AB || CD such that

AO = x - 1

CO = BO = x + 1

OD = x + 4

Now,

$\rm In \: \triangle \: AOB \: and \: \triangle \: COD$

$\rm \: \angle \: AOB \: and \: \angle \: COD \: \: \{vertically \: opposite \: angles \}$

$\rm \: \angle \:ABO \: and \: \angle \: CDO \: \: \{alternate \: interior \: angles \}$

$\bf \: \triangle \: AOB \: \sim \: \triangle \: COD \: \: \: \{AA \: similarity \}$

$\bf\longmapsto\:\dfrac{AO}{CO} = \dfrac{BO}{DO}$

$\rm \longmapsto\:\dfrac{x - 1}{x + 1} = \dfrac{x + 1}{x + 4}$

$\rm \longmapsto\:(x - 1)(x + 4) = {(x + 1)}^{2}$

$\rm \longmapsto\: {x}^{2} - x + 4x - 4 = {x}^{2} + 1 + 2x$

$\rm \longmapsto\: 3x - 4 = 1 + 2x$

$\rm \longmapsto\: 3x - 2x= 1 +4$

$\bf\longmapsto \:x = 5$

7 0

3 years ago

A tenant rented a store to use as a real estate school at a base rent of $1,500 a month. Additionally, the tenant agreed to pay

allsm [11]

Answer:

3. $600,000

Step-by-step explanation:

We have been given that a tenant rented a store to use as a real estate school at a base rent of $1,500 a month. Additionally, the tenant agreed to pay 3% of gross annual sales over $200,000.

Let us find base annual rent.

$\text{Base annual rent}=\$1500\times 12\\\\ \text{Base annual rent}=\$18,000$

Let us find the amount of rent paid as 3% of gross annual sales.

$\$30,000-\$18,000=\$12,000$

Let us find amount of sales over $200,000 by dividing $12000 by 3% or 0.03.

$\frac{\$12,000}{0.03}=\$400,000$

Total sales would be $400,000 plus $200,000.

$\text{Total sales}=\$400,000+\$200,000\\\\ \text{Total sales}=\$600,000$

Therefore, the total sales for that year was $600,000 and 3rd option is the correct choice.

7 0

3 years ago

What are the Properties of 5* 90

Degger [83]

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6 0

3 years ago

Read 2 more answers

What is the formula for a confidence interval?

ikadub [295]

Answer:

a) The formula is given by mean $\pm$ the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.

b) $\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

If the distribution for X is normal or if the sample size is large enough we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Part a

The formula is given by mean $\pm$ the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.

Part b

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

5 0

3 years ago