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Nezavi [6.7K]
4 years ago
13

Please help me some one out there thank you

Mathematics
2 answers:
V125BC [204]4 years ago
7 0
There is a percent formula that can solve all of these...
is / of = % / 100

what percent is 32 out of 80...
% = x...because this is what we r looking for
is = 32
of = 80
now sub into the formula
32/80 = x/100
cross multiply because this is a proportion
(80)(x) = (32)(100)
80x = 3200
x = 3200/80
x = 40......so 32 is 40% of 80

12 is 60% of what number...
is = 12
% = 60
of = x

sub
12/x = 60/100
cross multiply
(60)(x) = (12)(100)
60x = 1200
x = 1200/60
x = 20.....so 12 is 60% of 20

what is 30% of 70
is = x
% = 30
of = 70

x / 70 = 30/100
(100)(x) = (30)(70)
100x = 2100
x = 2100/100
x = 21.....so 21 is 30% of 70

what is 40% of 75
is = x
% = 40
of = 75

x / 75 = 40/100
(100)(x) = (75)(40)
100x = 3000
x = 3000/100
x = 30....so 30 is 40% of 75

the pic
what is 40% of 35
is = x
% = 40
of = 35

x/35 = 40/100
(100)(x) = (35)(40)
100x = 1400
x = 1400/100
x = 14.....so 14 is 40% of 35....14 goes in the box




deff fn [24]4 years ago
4 0

Answer:

14

Step-by-step explanation:

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Answer:

We have the problem:

"Clare is in charge of getting snacks for a road trip with her friends and her dog. She has

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In this situation we have two variables:

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Y = number of snacks for her dog that she buys. Each one of these costs $9.

The total cost, in this case, can be written as:

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And we know that she has $35 to spend, so she can spend $35 or less in the store, then we have the inequality:

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3 years ago
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iVinArrow [24]
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Find the slope and the y-intercept of the line y=9x-8
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Step-by-step explanation:

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Read this E[2X^2 â€" Y].
djyliett [7]

Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2<em>X </em>² - <em>Y</em>.

If you don't know how <em>X</em> or <em>Y</em> are distributed, but you know E[<em>X</em> ²] and E[<em>Y</em>], then it's as simple as distributing the expectation over the sum:

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Or, if you're given the expectation and variance of <em>X</em>, you have

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