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mr Goodwill [35]
3 years ago
9

18+24+3+4x6=6x(4+6)=____+_____

Mathematics
2 answers:
serg [7]3 years ago
3 0

One option for the answer would be -(9+9)

Nataly_w [17]3 years ago
3 0

-(9+9) this is the correct answer

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22.4 miles for gas :]
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Which ratio would help find the distance the person is from the flag pole ¨X¨ if the angle is elevation of 30 degrees.
WINSTONCH [101]

Answer:

There are three major trignometric ratios in mathematics and they are:

sine(sin), cosine(cos) and tangent(tan). A popular acronym is used in recalling the formula for each ratio and it is: SOH-CAH-TOA.

Sine(x) = Opp/Hyp

Cosine(x) = Adj/Hyp

Tangent(x) = Opp/Adj

Now, the Hyp is the hypothenus of the triangle and it is the side opposite to angle 90. The opposite and adjacent is kind of relative depending on the angle been considered. For this case, we are considering angle 30 which the opposite side is 60 and the remaining side becomes the adjacent

Step-by-step explanation:

tan 30 = 60/x

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2 years ago
Find the absolute value and the opposite of the integer. –98
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<span>Absolute value of -98 is 98

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Does anyone ply Pokémon go ?
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Step-by-step explanation:

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The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th
choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

f_x(x) = \dfrac{1}{1500} ; o \le x \le   \  1500

The function of the insurance is:

I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \  \ \ \ 250 \le x \le 1500}} \right.

Hence, the variance of the insurance can also be an account forum.

Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2

here;

E[I(x)] = \int f_x(x) I (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}

\dfrac{5}{12} \times 1250

Similarly;

E[I^2(x)] = \int f_x(x) I^2 (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}

\dfrac{5}{18} \times 1250^2

∴

Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]

Finally, the standard deviation  of the insurance payment is:

= \sqrt{Var(I(x))}

= 1250 \sqrt{\dfrac{5}{48}}

≅ 404

4 0
2 years ago
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