The student buys 3 small notebooks and 3 large notebooks
Answer:
x = 9
Step-by-step explanation:
60 + 6x + 16 = 13x + 13
6x - 13x = 13 - 16 - 60
- 7x = - 63
- x = - 63/7
- x = - 9
x = 9
Answer:
You can use Pythagorean Theroum, its not that hard. Use the formule a^2+b^2=c^2
The a is one side, the b is also another side but the C is the hypot use. The hypotunes (the largest side of a triangle) is usually the diagonal of the triangle like the one thats the longest.
(I’m gonna do a few)
1) 10^2+7^2=c^2
100+49=c^2
149=c^2
square root of 149 is about 12.21
(Skipped to 3 because of different example)
3) We know the hypotenuse but we don’t know B
so
16^2+b^2=27^2
256+b^2=729
b^2=473
About 21.75
6) Well this is a trapezoid and we want to find the side
So the two triangle’s sides are 17 and 19
We know 17 and 19 becuase the 17 was stated and the 19 was equal on both sides
use pythagoream theorem
17^2+b^2=19^2
289+b^2=361
B^2=72
8.49
Now thats the triangle’s sides
Now we double it becuase there are 2 of them
8.49(2)=16.98
Now we subtract that from 31
31-16.98=14.02
x=14.02
(I’d do more but I have no more space)
Answer:
a.
b. The fret should be placed 25 cm far from the bridge.
c. So, the fraction of string at which the fret is placed is .
Step-by-step explanation:
We are given,
The function representing the distance of a fret from the bridge by ,
where r = length of the root note string and n = number of notes higher than root note.
Now, Louis want to produce notes on a 50 com string. This gives r = 50.
Thus, .
1. It is required to produce notes which are 1 octave ( 12 notes ) higher than the root note. This gives that n = 12.
So, we get, r = 50 and n = 12 which gives us the function as,
a.
i.e.
i.e.
i.e.
b. Thus, the fret should be placed 25 cm far from the bridge.
Now, as the fret is placed 25 cm far on the string having length 50 cm.
c. So, the fraction of string at which the fret is placed is i.e. .