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pickupchik [31]
4 years ago
9

If the numbers 1, 2, 4, 8, 16, 32, 64, 128 and 256 are arranged in a 3x3 array (table) so that he product of the numbers in any

row or column is the same, what is this product?
Mathematics
2 answers:
musickatia [10]4 years ago
8 0
I did it by recognizing that they were all powers of two and that exponents add...so we are looking for a standard magic square for the number 0 thru 8, since 1, 2, ..., 256 are the numbers 2^0 thru 2^8...
The numbers are


128, 4, 8
1, 16, 256
32, 64, 2
Each row, column and diagonal's product is 2^12 or 4096.
Good problem

GrogVix [38]4 years ago
6 0

Answer:

for the question:

Which table represents an exponential function?

A.               B.                C.

it is the exponential function of 4

Step-by-step explanation:

you need to look for the exponential value of 4^1, then look for the value of 4^2, then so on, until you see that it is a function table of the exponential values of 4.

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3 years ago
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Step-by-step explanation:

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Serga [27]
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6 0
3 years ago
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What is the general rule for the arithmetic sequence? 15, 12, 9, 6, … A. 3n – 18 B. 6(3 – n) C. 3n + 12 D. 18 – 3n
slavikrds [6]
A1 = first term
a1 = 15
---------------------------------------------
d = common difference 
d = (second term) - (first term)
d = a2 - a1
d = 9-12
d = -3
The negative common difference indicates that the terms are decreasing
Each time we subtract 3, or add -3, to get the next term.
----------------------------------------------
nth term of arithmetic sequence
an = a1 + d(n-1)
an = 15 + (-3)(n-1)
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Answer is choice D
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4 years ago
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