d = 3 , a₁₂ = 40 and S
= 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a
= a₁ + (n-1)d</h3><h3>• S
=
[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =
[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
Step One
Factor f(x)
f(x) = (x + 5)(x - 2)
Step Two
The zeros occur when either (x + 5) = 0 or (x - 2) = 0
x + 5 = 0
x = -5
x - 2 =0
x = 2
Step 3
Record the zeros
(-5,0) or (2,0) <<<<<< answer.
Answer:
It could be 7π cm
Step-by-step explanation:
im sorry im not really sure
Answer:
68%
Step-by-step explanation:
85 divided by 125 = .68 * 100 = 68
