Hopefully try is works. Took me a few hrs to figure it out but I think I got it
Answer:
Probability that average height would be shorter than 63 inches = 0.30854 .
Step-by-step explanation:
We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.
Also, a random sample of 4 women from this population is taken and their average height is computed.
Let X bar = Average height
The z score probability distribution for average height is given by;
Z =
~ N(0,1)
where,
= population mean = 64 inches
= standard deviation = 4 inches
n = sample of women = 4
So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)
P(X bar < 63) = P(
<
) = P(Z < -0.5) = 1 - P(Z <= 0.5)
= 1 - 0.69146 = 0.30854
Hence, it is 30.85% likely that average height would be shorter than 63 inches.
Answer:
(3/2,0)
Step-by-step explanation:
Substitute 0 for y and solve for x
Answer:

Step-by-step explanation:
We need to find union of given sets
and 
We know by definition that union of two given sets say A and B is set C with all the unique and common values given in set A and B.
∴
∪
= 
Answer:
A is , 18.1058 B is , 24.91575
Step-by-step explanation: