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In-s [12.5K]
3 years ago
15

The diagram shown here represents

Mathematics
2 answers:
valentina_108 [34]3 years ago
5 0

Answer:  B) two intersecting planes.

Step-by-step explanation:

Definitions:

A line is a one -dimensional geometric figure that extends infinitely in both directions. It has only length but no width.

The intersection of two line is a point.

A plane is a two dimensional flat surface (like a sheet of paper)  and it extends infinitely . It has both length and width .

The intersection of two plane is a line.

By considering the given figure , we can easily see that the two planes ( ∵they have both length and width) are intersecting each other and the intersection is a line.

It means the correct answer regarding the given diagram : B) two intersecting planes.

Marysya12 [62]3 years ago
3 0

Answer:

THE ANSWER IS B

Step-by-step explanation:


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Solve the inequality 2x&gt;30+5/4x
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Answer:

Step-by-step explanation:

2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} }  \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0

x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }

case~2

if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0

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The answer is 7.75. Since there can not be 7.75 days, you can round that to 8 and say that it's almost 8 days. Hope this helps!

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