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3 years ago

What is the point-slope form of the line with slope 5 passing through (4,-2)

Mathematics

1 answer:

poizon [28]3 years ago

6 0

Answer:

y + 2 = 5(x - 4)

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = 5 and (a, b) = (4, - 2), hence

y - (- 2) = 4(x - 4)

y + 2 = 5(x - 4) ← in point- slope form

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Dmitry [639]

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3 years ago

Find the intersection points of the linear and quadratic functions shown below f(x)=2x-5 g(x)= x2+2x-21

Mice21 [21]

Answer:

$(-4,-13)$ and $(4,3)$ the intersection points.

Step-by-step explanation:

Intersection point of two functions is a common point which satisfies both the functions.

Given functions are,

$f(x)=2x-5$

$g(x)=x^2+2x-21$

For a common point of these functions,

$f(x)=g(x)$

$2x-5=x^2+2x-21$

$-5=x^2-21$

$0=x^2-16$

$x^2=16$

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$f(-4)=g(-4)=2(-4)-5$

$=-13$

For $x=4$ ,

$f(4)=g(4)=2(4)-5$

$=3$

Therefore, $(-4,-13)$ and $(4,3)$ the intersection points.

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3 years ago

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damaskus [11]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

30 points pls helppp

Phoenix [80]

Answer:

(y + 1) = 3( x +2)

Step-by-step explanation:

from equation,

y - y1 = m( x - x1)

given x1=2, y1= -1

m = 3 (slope)

substitute

y - (-1) = 3( x - 2)

ans: y+1= 3(x+2)

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2 years ago