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liubo4ka [24]
3 years ago
11

Find the center of the circle that can be circumscribed about mc043-1.jpgEFG with E(6, 4), F(6, 2), and G(10, 2)

Mathematics
1 answer:
loris [4]3 years ago
5 0
The center of the circle is f(6,10)
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Alma got to the playground at 2:45.she spent 20 minutes on the swings and 10 minutes on the jungle gym. She played on the slide
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Alma got home at 3:27

Step-by-step explanation:

2:45+30 min=3:15

3:15+12 min = 3:27

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Solve the system of linear equations by graphing.<br> Y = 3.2<br> y - 4= 32
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Solutions to equations of this form are ordered pairs (x, y), where the coordinates, ... When given linear equations with two variables, we can solve for one of the ... Since the solutions to linear equations are ordered pairs, they can be graphed using the rectangular coordinate system. ... 32. x−y=0 x − y = 0 ; {10, 20, 30}. Find

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7 % of 412 what is itttttt​
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Answer: 28.84

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5(x−3.8)=22 <br> please help find the x value
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Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125
Savatey [412]

we have that

300 + 150 + 75 +...

Let

a1=300\\ a2=150\\ a3=75

we know that

\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50

\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50

so

a(n+1)=an*0.50

Is a geometric sequence

Find the value of a4

a(4)=a3*0.50

a(4)=75*0.50

a(4)=37.5

Find the value of a5

a(5)=a4*0.50

a(5)=37.5*0.50

a(5)=18.75

Find S5

S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25

therefore

the answer is

581.25

Alternative Method

Applying the formula

S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25

therefore

the answer is

581.25

6 0
3 years ago
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