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liubo4ka [24]
3 years ago
11

Find the center of the circle that can be circumscribed about mc043-1.jpgEFG with E(6, 4), F(6, 2), and G(10, 2)

Mathematics
1 answer:
loris [4]3 years ago
5 0
The center of the circle is f(6,10)
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Write a real word problem that cold be solved by using the equation 3x- 25= 125
Kazeer [188]
<span>Two teams are playing basketball. Team 1 scored 3.5 times the number of points per basket. Team 2 scored 8 times the number of points per basket. They would've each scored the same amount of points if Team 1 had scored 54 more points.
Solve:
54+3.5x=8x :Write out the equation
-3.5x -3.5x :Subtract 3.5x from both sides to isolate the variable
54=4.5x :Simplify
/4.5 /4.5 :Divide by 4.5 on both sides
12=x :Answer=12
Next you would find each team's score:
8x= 8(12)= 96 :substitute and solve
Each team score is 96 points
(Note: Since each team score was equal, you don't have to solve for each team, just one and preferably the easier one, and that is the score that each team scored.) </span>
6 0
4 years ago
Read 2 more answers
Help please please please​
LekaFEV [45]

Answer:

There are 9 quarters and 3 nickels

Step-by-step explanation:

problems used: 0.5x+0.25y=3.09

x=y+6

so substitute what x is equal to into the problem

0.5(y+6)+0.25y=3.09  <--------- distribute

0.5y+3+0.25y=3.09     <--------- Combine like terms

0.3y+3=3.09 <----------- Subtract 3 on both sided to get y by itself

0.3y=0.9 <------------ Divide by 0.3 on both sides to get what y is equal to

y=3 <-------- now substitute to find what x is equal to

x=3+6

x=9

8 0
3 years ago
Read 2 more answers
Really need help guys!<br> Love you if you can solve them wiz steps!!!!
Marta_Voda [28]

Answer:

Step-by-step explanation:

x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3}  \\\sqrt{D}=4\sqrt{3}  \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}

c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16

d)\\A(6,2\sqrt{3}-2)}\\\sqrt{3} x+3y=\\\sqrt{3}(6)+3(2\sqrt{3} -2)=\\ 6\sqrt{3}+6\sqrt{3} -6=\\ 12\sqrt{3}-6

5 0
1 year ago
A 91square foot bathroom has a length of 13 feet.What<br> is the width of the bathroom??
Nadusha1986 [10]
7 feet long////////////

3 0
3 years ago
Read 2 more answers
Simplify the equations: -3(-2h+-3)
Alex17521 [72]

Answer:6h+9

Step-by-step explanation:

-3(-2h-3)

Open the brackets

6h+9

7 0
3 years ago
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