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Ksju [112]
2 years ago
8

How do you solve a unite rate

Mathematics
2 answers:
Lera25 [3.4K]2 years ago
5 0

Answer:

To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate.

Step-by-step explanation:

As an example, in this case, divide the numerator and denominator of 70/5 by 5, to get 14/1, or 14 students per class, which is the unit rate.

ExtremeBDS [4]2 years ago
5 0

Answer:

Depending on whether you are solving a unit rate from a graph or without a graph, you can the unit rate by dividing the y coordinates by the x coordinates. If you are looking for a simpler answer, then you simply divide whatever independant value by its dependent counterpart. For example, if you are looking for the price per object, then you would divide the price by the object! Lets say for a bundle of 10 toilet rolls it costs $11.55. You would divide 11.55/10 and get a unit price of $1.15 cents rounded to the hundredth decimal. I hope this helps! :)

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Abby buys 4 pencils and 2 erasers for 3.58. Michael buys 1 pencil and 6 erasers for 2.49. What is the cost of 1 pencil and 1 era
Dimas [21]

Answer:

pencils= .75 erasers= .29¢

Step-by-step explanation:

7 0
3 years ago
Need help!!!!! Thank you
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5 0
3 years ago
What does the digit 3 represent in the number 21,473,862,095
yuradex [85]

Answer:

It represents the millions place, so in this case 3,000,000

Step-by-step explanation:

4 0
2 years ago
If (5x− 4)(3x+ 7) = 15x²-ax-b,then find the value of a and b
Mkey [24]

Answer:

a=-23\\\\b=28

Step-by-step explanation:

Let's start by using distributive multiplication:

(a\pm b)(c\pm d)=ac\pm ad \pm bc \pm bd

So:

(5x-4)(3x+7)=15x^2+35x-12x-28\\\\

Grouping like terms:

15x^2 +(35x-12x)-28\\\\15x^2+23x-28

Now, 15x^2+23x-28 is equal to:

15x^2-ax-b

In this sense:

15x^2+23x-28=15x^2-ax-b

In order to satisfied the equality:

23x=-ax\hspace{10}(1)\\\\and\\\\-28=-b\hspace{10}(2)

Hence, from (1), let's solve for a:

23x=-ax\\\\-a=\frac{23x}{x} \\\\-a=23\\\\a=-23

And from (2), let's solve for b:

-28=-b\\\\b=28

Let's verify the result evaluating the values of a and b into the original equation:

(5x-4)(3x+7)=15x^2+23x-28=15x^2 -ax -b\\\\(5x-4)(3x+7)=15x^2+23x-28=15x^2 -(-23)x -(28)\\\\(5x-4)(3x+7)=15x^2+23x-28=15x^2 +23x -28

As you can see, the values satisfy the equation, therefore, we can conclude they are correct.

3 0
3 years ago
X^2 + 10x + 29 = 0<br> How do I solve this equation (imaginary numbers acceptable)
Leona [35]
X^2+10x+29=0

Quadratic Formula:
−b±√b^2−4(ac)/2a

Substitute the values :
a=1, b=−10, and c=29

into the quadratic formula and solve for
x.

10±√(−10)^2−4•(1•29)/ 2•1

Simplify.

Answer: x=5±2i
4 0
2 years ago
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