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Lemur [1.5K]
3 years ago
7

How does the law of conservation of mass apply to this reaction: C2H4 + O2 → H2O + CO2?

Physics
2 answers:
zhannawk [14.2K]3 years ago
7 0

The correct answer is D. The law of conservation of mass states that in a system matter can neither be created or destroyed, hence atoms of each element on reactant side should equal atoms of each element on product side. In the unbalanced equation:

C_2H_4 + O_2 ==> H_2O + CO_2, the are 2 carbon atoms on reactant side as opposed to 1 carbon atom on product side,  there are 4 hydrogen atoms on reactant side as opposed to 2 hydrogen atoms on product side, and there are 2 oxygen atoms on reactant side as opposed to 3 atoms of oxygen on product side. To balance the equation we add a coefficient of 3 on O_2 and on the product side we put a coefficient of 2 on both water H_2O and carbon dioxide CO_2.

C_2H_4 + 3O_2 ==> 2H_2O + 2CO_2.

kicyunya [14]3 years ago
4 0

The answer is a

the equation needs to be balanced. There are fewer oxygen atoms in the equation than hydrogen or a carbon

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Answer:

true

Explanation:

the sun warms the atmosphere and warms the air which drives our weather

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State of motion is described by
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Classify each process according to whether it does or does not produce a new substance.
AlexFokin [52]

The processes under chemical change are: cooking an egg, fireworks exploding, and rusting of a metal tool.

The processes under physical change are: melting ice, evaporating puddle of water, and dissolving of salt in water.

Given:

The following process:

  1. cooking an egg
  2. melting ice
  3. fireworks exploding
  4. evaporating puddle of water
  5. rusting of a metal tool
  6. Dissolving of salt in water

To find:

The classify the processes in whether it does or does not produce a new substance.

Solution:

  • Chemical change is the change when a new substance is formed due to a change in the chemical composition of the substance.
  • Physical change is the change in which no change in chemical composition takes place and the identity of the substance remains the same.
  • Cooking an egg

Chemical change, due to change in atomic arrangement egg get solidified on cooking, a new substance is formed.

  • Melting ice

Physical change, change in the state of matter is taking from solid to liquid, no new substance is formed.

  • Firework exploding

Chemical change. formation of carbon dioxide gas and sound energy, anew substance formed

  • Evaporating puddle of water

Physical change, change in the state of matter is taking from liquid to gas, no new substance is formed.

  • Rusting of metal tool

Chemical change, formation of oxides on the surface of the metal tool due to reaction between air and metal, a new substance is formed.

  • Dissolving of salt in water

Physical change, ions of salt in the solid state are changing into aqueous ions with no formation of new substance, no new substance is formed.

The processes under chemical change are: cooking an egg, fireworks exploding, and rusting of a metal tool.

The processes under physical change are: melting ice, evaporating puddle of water, and dissolving of salt in water.

Learn more about physical change and chemical change here:

brainly.com/question/864557?referrer=searchResults

brainly.com/question/13316655?referrer=searchResults

7 0
3 years ago
A sock stuck to the inside of the clothes dryer spins around the drum once every 2.0 s at a distance of 0.50 m from the center o
Rashid [163]

a) 1.57 m/s

The sock spins once every 2.0 seconds, so its period is

T = 2.0 s

Therefore, the angular velocity of the sock is

\omega=\frac{2\pi}{T}=\frac{2\pi}{2.0}=3.14 rad/s

The linear speed of the sock is given by

v=\omega r

where

\omega is the angular velocity

r = 0.50 m is the radius of the circular path of the sock

Substituting, we find:

v=(3.14)(0.50)=1.57 m/s

B) Faster

In this case, the drum is twice as wide, so the new radius of the circular path of the sock is twice the previous one:

r' = 2r = 1.00 m

At the same time, the drum spins at the same frequency as before, therefore the angular frequency as not changed:

\omega' = \omega = 3.14 rad/s

Therefore, the new linear speed would be:

v'=\omega' r' = \omega (2r)

And substituting,

v'=(3.14)(1.00)=3.14 rad/s = 2v

So, we see that the linear speed has doubled.

8 0
3 years ago
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