Answer:
Oh I am sorry this is my first time on brainly i dont how to exit and sorry but dont know the answer
Explanation:
Explanation:
first you have to find accelerarion, it is given that the initial velocity(u) is 3 m/s, distance travelled(s) be 2m finall it came to rest so final velocity be 0m/s
now using the 3rd law of motion
v^2=u^2+2as
0=9+2a2
a= -9/4m/s^2
now force=mass×accelration
=2kg×(-9/4)m/s^2
=4.5 N
4.5 newton force applied on the book!
✌️:)
The strength of the electric field on the point charge at this distance will be 4000 V/m.
<h3>What is the strength of the electric field?</h3>
The strength of the electric field is the ratio of electric force per unit charge.
The given data in the problem is;
Qis the unit charge = 4.0 × 10⁻⁶ C
E is the strength of the electric field
R is the distance from point charge = 3 m
The strength of the electric field is;
Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.
To learn more about the strength of the electric field refer to the link;
brainly.com/question/15170044
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You're most likely to build up enough static charge to receive a shock by walking around in a carpeted restaurant in the desert. (A)
Walking on carpet is the fastest way to accumulate charge, and the dry desert air prevents the charge from dribbling off of you and away.
When I walked on stones in the Sinai Desert, the dry wind with a little bit of sand or dust in it built up enough static charge on me that I got a shock every time I stood less than a foot away from my partner.
I had the same experience a few years later near Ouarzazate in the interior of Morocco.
When you hear people say "the desert is dry", they mean it's <em>DRY ! </em>
I think the right answer for this question is : 138 because the boy is just 15 year old but he has resting heart rate of 70
