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Katarina [22]
3 years ago
7

Name at least two clouds types in each level, with their characteristics:

Physics
2 answers:
sergejj [24]3 years ago
6 0

Answer:

High-Level Clouds

Cloud types include: cirrus and cirrostratus.

High-level clouds form above 20,000 feet (6,000 meters) and since the temperatures are so cold at such high elevations, these clouds are primarily composed of ice crystals. High-level clouds are typically thin and white in appearance, but can appear in a magnificent array of colors when the sun is low on the horizon.

Mid-Level Clouds

Cloud types include: altocumulus, altostratus.

The bases of mid-level clouds typically appear between 6,500 to 20,000 feet (2,000 to 6,000 meters). Because of their lower altitudes, they are composed primarily of water droplets, however, they can also be composed of ice crystals when temperatures are cold enough.

Low-level Clouds

Cloud types include: nimbostratus and stratocumulus.

Low clouds are of mostly composed of water droplets since their bases generally lie below 6,500 feet (2,000 meters). However, when temperatures are cold enough, these clouds may also contain ice particles and snow.

Sholpan [36]3 years ago
5 0

Answer:

Low- Level:  Cumulus and stratus

Cumulus have tops that are rounded, puffy, and a brilliant white when sunlit, while their bottoms are flat and relatively dark.

Stratus clouds hang low in the sky as a flat, featureless, uniform layer of grayish cloud.

Mid-Level:  Altocumulus and nimbostratus

Altocumulus have white or gray patches that dot the sky in large, rounded masses or clouds that are aligned in parallel bands.

Nimbostratus clouds cover the sky in a dark gray layer. They are thick enough to blot out the sun

High-Level: Cirrus and cirrocumulus

Cirrus are thin, white, wispy strands of clouds that streak across the sky. They are made up of tiny ice crystals rather than water droplets.

Cirrocumulus clouds are small, white patches of clouds often arranged in rows that live at high altitudes and are made of ice crystals.

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If an object has a positive charge, are the electrons from another object more likely to be attracted to it or to repel it?
Vlad1618 [11]

Answer:

attracted

Explanation:

Electrons are negative.

A positively charged object will attract a negatively charged object

3 0
2 years ago
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You and a friend are studying late at night. There are three 110 W light bulbs and a radio with an internal resistance of 56.0 Ω
Sliva [168]

Answer:

The total electrical power we are using is: 1316 W.

Explanation:

Using the ohm´s law V=I*R and the formula for calculate the electrical power, we can find the total electrical power that we are using. First we need to find each electrical power that is using every single component, so the radio power is:I=\frac{V}{R}=\frac{110 (v)}{56(ohms)}=1.96(A), so the radio power is: P=I*V=1.96(A)*110(v)=216(W), then we find the pop-corn machine power as: P=I*V=7(A)*110(v)=770(W) and finally there are three light bulbs of 110(W) so: P=3*110(W)=330(W) and the total electrical power is the adding up every single power so that: P=330(W)+770(W)+216(W)=1316(W).

8 0
3 years ago
Describe how the design of a vacuum flask keeps the liquid inside hot ?
JulijaS [17]
The gap between the two flasks is partially evacuated of air creating a near vacuum which significantly reduces heat transfer by conduction or convection 
3 0
3 years ago
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Q1. In a 100m track event, the time taken by four runners is 10 sec., 10.2 sec., 10.4 sec and 10.6 sec. Find the ratio of their
Anna35 [415]
Distance (s)=100m
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v=\frac{s}{t}
we get
V₁=\frac{100}{10}
V₁=10m/s

V₂=\frac{100}{10.2}
V₂=9.8m/s

V₃=\frac{100}{10.4}
V₃=9.61 m/s

V₄=\frac{100}{10.6}
V₄=9.43 m/s

V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43
8 0
3 years ago
Um avião, após deslocar-se 120 km para nordeste (NE), desloca-se 160 km para sudeste (SE). Sendo um quarto de hora o tempo total
Svetach [21]

Answer:

E) 800 km/h

Explanation:

The computation of the average vector velocity module of the plane, at that time is shown below:

The displacement vector is

d^2 = d1^2 + d2^2

where,

d1 = northeast displacement

d2 = southeast displacement

Now

d^2 = (120)^2 + (160)^2

= 14400 + 2560

= 40000

= √40000

d = 200 km

Now the average velocity is

V = ΔS ÷ Δt

= 200 ÷ 1 ÷ 4

= 200 × 4

=  800 km/h

4 0
3 years ago
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