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Katarina [22]
3 years ago
7

Name at least two clouds types in each level, with their characteristics:

Physics
2 answers:
sergejj [24]3 years ago
6 0

Answer:

High-Level Clouds

Cloud types include: cirrus and cirrostratus.

High-level clouds form above 20,000 feet (6,000 meters) and since the temperatures are so cold at such high elevations, these clouds are primarily composed of ice crystals. High-level clouds are typically thin and white in appearance, but can appear in a magnificent array of colors when the sun is low on the horizon.

Mid-Level Clouds

Cloud types include: altocumulus, altostratus.

The bases of mid-level clouds typically appear between 6,500 to 20,000 feet (2,000 to 6,000 meters). Because of their lower altitudes, they are composed primarily of water droplets, however, they can also be composed of ice crystals when temperatures are cold enough.

Low-level Clouds

Cloud types include: nimbostratus and stratocumulus.

Low clouds are of mostly composed of water droplets since their bases generally lie below 6,500 feet (2,000 meters). However, when temperatures are cold enough, these clouds may also contain ice particles and snow.

Sholpan [36]3 years ago
5 0

Answer:

Low- Level:  Cumulus and stratus

Cumulus have tops that are rounded, puffy, and a brilliant white when sunlit, while their bottoms are flat and relatively dark.

Stratus clouds hang low in the sky as a flat, featureless, uniform layer of grayish cloud.

Mid-Level:  Altocumulus and nimbostratus

Altocumulus have white or gray patches that dot the sky in large, rounded masses or clouds that are aligned in parallel bands.

Nimbostratus clouds cover the sky in a dark gray layer. They are thick enough to blot out the sun

High-Level: Cirrus and cirrocumulus

Cirrus are thin, white, wispy strands of clouds that streak across the sky. They are made up of tiny ice crystals rather than water droplets.

Cirrocumulus clouds are small, white patches of clouds often arranged in rows that live at high altitudes and are made of ice crystals.

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Children in a tree house lift a small dog in a basket 4.90m up to their house. If it takes 201J of work to do this, what is the
scZoUnD [109]

Answer:

4.18 kg.

Explanation:

Work done: Work is said to be done when ever a force move a body through a given distance. The S.I unit of work done is Joules (J)

Mathematically, work done is expressed as

W' = F×d.................... Equation 1

Where W' = work done, F = force , d = distance.

making F the subject of the equation,

F = W'/d............................. Equation 2

Note: The force need to lift the small dog n a basket = combined weight of the dog ans the basket.

Therefore,

W = F

Where W = combined weight of the dog and the basket.

Also

W = Mg

M = W/g............................. Equation 3

Where M = combined mass of the dog and the basket, g = acceleration due to gravity.

Given: W' = 201 J, d = 4.90 m.

Substitute into equation 2

F = 201/4.9

F = 41.02 N.

Since F = W = 41.02 N and g = 9.81 m/s²

Substitute these values into equation 3

M = 41.02/9.81

M = 4.18 kg.

Thus the combined mass of the dog and the basket = 4.18 kg.

4 0
3 years ago
a block with a mass of 3 kg is swung on a cord in a horizontal circle with a radius of 2m. the speed of the block is 6m/s^. the
Ivenika [448]

Given Information:  

Mass = m = 3 kg

Speed = v = 6 m/s  

Radius = r = 2 m

Required Information:  

Magnitude of the acceleration = a = ?  

Answer:

Magnitude of the acceleration = 18 m/s²

Explanation:

The acceleration of the block traveling along a circular path with some velocity is given by

a = v²/r

a = 6²/2

a = 36/2

a = 18 m/s²

Therefore, the magnitude of the acceleration of the block is most nearly equal to 18 m/s².

Bonus:

The corresponding force acting on the block can be found using

F = ma (a = v²/r)

F = mv²/r

7 0
3 years ago
Read 2 more answers
1) A fan is to accelerate quiescent air to a velocity of 8 m/s at a rate of 9 m3/s. Determine the minimum power that must be sup
azamat

Answer:

\dot{W} = 339.84 W

Explanation:

given data:

flow Q = 9 m^{3}/s

velocity = 8 m/s

density of air = 1.18 kg/m^{3}

minimum power required to supplied to the fan is equal to the POWER POTENTIAL of the kinetic energy and it is given as

\dot{W} =\dot{m}\frac{V^{2}}{2}

here \dot{m}is mass flow rate and given as

\dot{m} = \rho*Q

\dot{W} =\rho*Q\frac{V^{2}}{2}

Putting all value to get minimum power

\dot{W} =1.18*9*\frac{8^{2}}{2}

\dot{W} = 339.84 W

7 0
3 years ago
A tennis ball is dropped from 1.43 m above the
Rudiy27

Answer:

-5.29 m/s

Explanation:

Given:

y₀ = 1.43 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.43 m)

v = -5.29 m/s

4 0
4 years ago
A wooden block with mass 1.05 kg is placed against a compressed spring at the bottom of a slope inclined at an angle of 35.0 deg
Svet_ta [14]

Answer:

Explanation:

energy stored in spring initially

= kinetic + potential energy of block + energy dissipated by friction

= 1/2 mv² + mgh + μ mgcosθ x  d

m is mass , v is velocity at top position , h is vertical height , μ is coefficient of friction ,θ is angle of inclination of plane

= m (1/2 v² + gh + μ gcosθ x  d )

= 1.05 ( .5 x 5.1² + 9.8 x 4.9 sin35 + .55 x 9.8 cos35 x 4.9 )

= 1.05 ( 13.005 + 27.543 + 21.635)

= 65.3 J .

4 0
3 years ago
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