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Musya8 [376]
3 years ago
7

In the figure, a 3.7 kg block slides along a track from one level to a higher level after passing through an intermediate valley

. The track is frictionless until the block reaches the higher level. There a frictional force stops the block in a distance d. The block's initial speed is v0 = 7.4 m/s, the height difference is h = 1.2 m, and μk = 0.627. Find d.
Physics
1 answer:
JulijaS [17]3 years ago
3 0

Answer:

1/2 of an answer is zero answer

Explanation:

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you push a book a distance of 5 meters with a force of 10 newtons for 2 seconds how much work did you do on the book
GrogVix [38]

Answer:

50 J

Explanation:

Work, W=Fd where F is the applied force and d is the distance

Substituting 10 N for F and 5 m for d then work done on the book can be expressed as

W=10 N* 5 m=50 Nm= 50 J

Therefore, the work done is equivalent to 50 J

3 0
2 years ago
A converging lens brings rays of light together at a focal point. The bending of light rays is the result ofA. A combination of
Tcecarenko [31]

Answer:

.C. Refraction of light passing through the lens.

Explanation:

The convergence or divergence of the rays of light is only due to refraction of light.  When a ray of light is made to pass through a lens, it bend's from it's original path. This bending of light from its original path is called Refraction. Whereas in Reflection the ray of light is reflected back into the same medium.

Hence the correct option is C. Refraction of light passing through the lens.

5 0
3 years ago
Two motorcycles travel along a straight road heading due north. At t = 0 motorcycle 1 is at x = 50.0 m and moves with a constant
Dafna1 [17]

Answer:

Vf = 23 m/s

Explanation:

First we need to find the distance covered by the motorcycle 2 when it passes motorcycle 1. Using the uniform speed equation for motorcycle 1:

s₁ = v₁t₁

where,

s₁ = distance covered by motorcycle 1 = ?

v₁ = speed of motorcycle 1 = 6.5 m/s

t₁ = time = 10 s

Therefore,

s₁ = (6.5 m/s)(10 s)

s₁ = 65 m

Now, for the distance covered by motorcycle 2 at the meeting point. Since, the motorcycle started 50 m ahead of motorcycle 2. Therefore,

s₂ = s₁ + 50 m

s₂ = 65 m + 50 m

s₂ = 115 m

Now, using second equation of motion for motorcycle 2:

s₂ = Vi t + (1/2)at²

where,

Vi = initial velocity of motorcycle 2 = 0 m/s

Therefore,

115 m = (0 m/s)(10 s) + (1/2)(a)(10 s)²

a = 230 m/100 s²

a = 2.3 m/s²

Now, using 1st equation of motion:

Vf = Vi + at

Vf = 0 m/s + (2.3 m/s²)(10 s)

<u>Vf = 23 m/s</u>

5 0
3 years ago
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Yuki888 [10]
Most stars are much smaller compared to the sun.
4 0
2 years ago
You find yourself in the middle of a frozen lake with a surface so slippery (ms = mk = 0) you cannot walk. However, you happen t
EleoNora [17]

Answer:Maybe if you would slide on your stomach you can get out of there.

Explanation:

8 0
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