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Musya8 [376]
3 years ago
7

In the figure, a 3.7 kg block slides along a track from one level to a higher level after passing through an intermediate valley

. The track is frictionless until the block reaches the higher level. There a frictional force stops the block in a distance d. The block's initial speed is v0 = 7.4 m/s, the height difference is h = 1.2 m, and μk = 0.627. Find d.
Physics
1 answer:
JulijaS [17]3 years ago
3 0

Answer:

1/2 of an answer is zero answer

Explanation:

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If a net force applied to an object is equal to zero, then the forces that are acting on an object are considered.
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Answer:

The mass will accelerate. Balanced Forces: When forces are in balance, acceleration is zero. Velocity is constant and there is no net or unbalanced force. A plane will fly at constant velocity if the acceleration is zero.

Explanation:

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A wagon with an initial velocity of 2 m/s and a mass of 60 kg, gets a push with 150 joules of
Aleks04 [339]

Answer:

v_f = 3 m/s

Explanation:

From work energy theorem;

W = K_f - K_i

Where;

K_f is final kinetic energy

K_i is initial kinetic energy

W is work done

K_f = ½mv_f²

K_i = ½mv_i²

Where v_f and v_i are final and initial velocities respectively

Thus;

W = ½mv_f² - ½mv_i²

We are given;

W = 150 J

m = 60 kg

v_i = 2 m/s

Thus;

150 = ½×60(v_f² - 2²)

150 = 30(v_f² - 4)

(v_f² - 4) = 150/30

(v_f² - 4) = 5

v_f² = 5 + 4

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7 0
3 years ago
Hello people ~
Pepsi [2]

Answer:

Potential

Explanation:

The most accurate term is Electrostatic potential energy

  • It is denoted as UC

It's named like this because the force between charges or electrons is called electrostatic force .

5 0
3 years ago
A boat heads directly across a river. Its speed relative to the water is 3 m/s. It takes it 539 seconds to cross, but it ends up
nikklg [1K]

Answer:

3.24 m/s

Explanation:

Suppose that the boat sails with velocity (relative to water) direction being perpendicular to water stream. Had there been no water flow, it would have ended up 0m downstream

Therefore, the river speed is the one that push the boat 662 m downstream within 539 seconds. We can use this to calculate its magnitude

v_r = 662 / 539 = 1.23 m/s

So the boat velocity vector relative to the bank is the sum of of the boat velocity vector relative to the water and the water velocity vector relative to the bank. Since these 2 component vectors are perpendicular to each other, the magnitude of the total vector can be calculated using Pythagorean formula:

v = \sqrt{v_b^2 + v_r^2} = \sqrt{3^2 + 1.23^2} = \sqrt{9 + 1.5129} = \sqrt{10.5129} = 3.24 m/s

5 0
3 years ago
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