I’m sure your answer it’s the second one 48:70:24.3 cm
Answer:
cos(O) = 39 / 89
Step-by-step explanation:
Given:
ΔOPQ, where
∠Q=90°
PO = 89
OQ = 39
QP = 80
cosine of ∠O?
cos(O) = Adjacent / Hypotenuse
cos(O) = 39 / 89
C. Chana’s and Josiah’s distance from the starting line at the time when chana catches up to Josiah
7 because the 3 is the coefficient and the x is the variable. The + is the operator so that leaves you the 7
