It must be B banana because it is the smallest compared to the other ones
Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
The following set of data represents letter grades on term papers in a rhetoric class: A,A,A,B,B,B,B,C,C,C,C,C,C,C,C,C,D,D,D,F.
Viktor [21]
Answer:
c. Mode
Step-by-step explanation:
Mean is the average obtained by adding all values and then dividing by the size of the values. Here, adding A and B etc is not clear.
Median is the middle value of a set of numeric values. To find a median, values should be sort-able from smallest to the largest. If there is no unique middle value, then the average of the middle values has to be taken. Here, average of the two different grades is not clear.
Mode is the value that occurs most often. Clearly C occurs most often.
Mid-range value is the mean of the difference between largest value and the smallest value. Here, difference between A and F is not clear.
Mean,median,Mid-range are applied to numeric values where mode is also suitable for categorical values.
Therefore, the most appropriate measure of central tendency for the data described is mode
Answer:
no change in area
Step-by-step explanation:
The original area is
A = 12*5 = 60 ft^2
The new length and width
l = 12 + .25 (12) = 12+3 =15
w = 5 - .2 (5) =5-1 = 4
The new area is
A = l*w =15*4 = 60 ft^2
The area is the same
