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ratelena [41]
3 years ago
14

A mechanic gives a survey to all of his customers asking them to rate the quality of the service they received. He then keeps tr

ack of how many customers return to the shop for additional services during the next six months. Last year, the results showed that of the customers who reported high quality service, 20% returned for additional services. What conclusion can be drawn from this study?
A Some customers who rate their service as high quality return for additional services.


B Most customers who rate their service as high quality return for additional services.


C High quality services cause customers to return for additional services.


D Customers who will return for additional services report a high quality of service.
Mathematics
1 answer:
sammy [17]3 years ago
8 0
The answer is letter A. 
In the paragraph, only 20% of the customers who voted highly returned. From this, we can only say that some of those people came back. Most means a majority of the population and some means a minority. 
Also, we can't say C or D because we do not have any information regarding customers who voted badly. C says that high rating make people come back, but we do not have any information on the people who voted mediocre. We can not say C. D says that customers who come back will be high rating customers. We do not know if any customers who voted low came back, so we are unable to say D. 
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and 3/8 is lower than 0.5: we know this because a bigger number, 4/8 is equal to 0.5

so it's closer to 0!
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Each of the 25 balls in a certain box is either red, blue, or white and has a number from 1 to 10 painted on it. If one ball is
LekaFEV [45]

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The probability of selecting a red ball, a blue ball or a white ball is unknown.

Step-by-step explanation:

The probability of selecting a red ball, a blue ball or a white ball is unknown.

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8 0
3 years ago
A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome
Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

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P (A remaining passenger will arrive), <em>p</em> = 0.52

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.

(1)

Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

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Thus, the probability that the flight has empty seats is 0.4625.

4 0
3 years ago
Evaluate $\dfrac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}$.
Pavlova-9 [17]
<h3>Answer:  4</h3>

========================================================

Work Shown:

\frac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}\\\\\frac{2\sqrt{36*2}}{\sqrt{4*2}+\sqrt{2}}\\\\\frac{2\sqrt{36}*\sqrt{2}}{\sqrt{4}*\sqrt{2}+\sqrt{2}}\\\\\frac{2*6*\sqrt{2}}{2*\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{2\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{3\sqrt{2}}\\\\\frac{12}{3}\\\\4

Note in step 2, I factored each number in the square root to pull out the largest perfect square factor. From there, I used the rule that \sqrt{A*B} = \sqrt{A}*\sqrt{B} to break up the roots.

8 0
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