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2 years ago

Find the pattern and use it to list the next two terms in the sequence.

Mathematics

1 answer:

lidiya [134]2 years ago

8 0

Answer:

Step-by-step explanation:

a₁ = -3 = (-1)¹×3

a₂ = 6 = (-1)²×2×3

a₃ = -28 = (-1)³×2²×7

a₄ = 72 = (-1)⁴×2³×3²

a₅ = -360 = (-1)⁵×2³×3²×5

a₆ = 2160 = (-1)⁶×2⁴×3³×5

That's as far as I got. I can predict that a₇ is a multiple of -32 and a₈ is a multiple of 64, but I don't see the pattern with the other factors.

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A sequence of 7 numbers starts with 8. The second number in the sequence is unknown and may be positive or negative. The third t

scoray [572]

Answer:

Explanation:

$a_1=8,a_7=0$

Since the third term is the sum of the two previous terms

$a_3=a_2+a_1$

$a_7=a_6+a_5$

$a_7=a_5+a_4+a_4+a_3$

Continuing in like manner

$a_7=5a_3+3a_2$

Since $a_3=a_2+a_1$

$a_7=5(a_2+a_1+3a_2$

$a_7=5a_2+5a_1+3a_2$

$a_7=8a_2+5a_1$

Recall: $a_1=8,a_7=0$

$0=8a_2+5*8$

$8a_2=-40$

$a_2=-5$

The sequence is therefore:

8,-5,3,-2,1,-1,0

The sum of the seven numbers is 4.

8 0

2 years ago

PLEASE HELP!!!!! What is the value of x in the matrix equation below?

Brums [2.3K]

The given matrix equation is,

$1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]$ .

Multiplying the matrices with the scalars, the given equation becomes,

$\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\$