Answer:
D = m/v.
Explanation:
The density of a substance is the relationship between the mass of the substance and how much space it takes up (volume). The mass of atoms, their size, and how they are arranged determine the density of a substance. Density equals the mass of the substance divided by its volume;
Which of the following is a property of bases?
B. Feels slippery
This is most likely the Chemical Properties of Bases
The Chemical Properties of Bases include:
- Bases change the colour of litmus from red to blue.
- They are bitter in taste.
- Bases lose their basicity when mixed with acids.
- Bases react with acids to form salt and water. This process is called Neutralisation Reaction(Read).
- They can conduct electricity.
- Bases feel slippery or soapy.
- Some bases are great conductors of electricity.
- Bases like sodium hydroxide, potassium hydroxide, etc are used as electrolytes.
- Alkalis are bases that produce hydroxyl ions (OH-) when mixed with water.
- Strong alkalis are highly corrosive in nature whereas other alkalis are mildly corrosive.
- The pH value of bases ranges from 8-14.
Alkalis and ammonium salts produce ammonia.
- Hydrogen gas is evolved when metals react with a base.
- Bases are classified on the basis of strength, concentration and acidity.
- The different kinds of acids are strong base acid, weak base acid, concentrated base, dilute base, monoacidic base, diacidic base and triacidic base.
Answer:
The relevant equation is:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
Explanation:
1 mol of calcium carbonate can react to 2 moles of Hydrochloric acid to produce 1 mol of water, 1 mol of calcium chloride and 1 mol of carbon dioxide.
The formed CO₂ is the reason why you noticed bubbles as the reaction took place
Answer:
12 liters of oxygen are released from the decomposition of the peroxide.
Explanation:
The hydrogen peroxide is decomposed by this reaction:
2 H₂O₂ (l) → 2 H₂O (l) + O₂ (g)
Molar mass H₂O₂ = 34 g/m
Moles of peroxide: 36.5 g / 34 g/m = 1.07 moles
Ratio is 2:1, so 2 moles of peroxide will be decomposed in 1 mol of oxygen (exactly the half)
1.07 moles of peroxide will be decomposed in the half of moles, 0.54 moles
Let's apply the Ideal Gases law Equation to solve the volume
1 atm . V = 0.54 mol . 0.082 .273K
V = (0.54 mol . 0.082 .273K) / 1 atm → 12L
Q = mCΔT
ΔT = 29.2 - 20 = 9.2 °C
Q = 120 x 4.184 x 9.2
Q = 4,619.1 Joules