Answer:
Explanation:
The intermediates are the products of all the steps of the reaction pathway, with the exception of the last one. So the intermediates will be:
- N2O2 from the first step
- N2O from the second step
The list from reactant to final product:
<em>Note: the water is considered a by-product, given that is not the product of interest in this steps.</em>
Answer: a. BaO
Explanation:
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Here element barium is having an oxidation state of +2 called as 
cation and 
is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral 
Answer:
- 1a) BaClO₃(s) → BaCl₂(g) + O₂(g)
- 1b) Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)
- 1c) Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)
- 2a) Calcium hydroxide and hydrogen gas
- 2b) Tin(II) silicate and Lead(IV) permanganate
- 2c) Magnesium oxide and water
- 2f) Calcium chloride and iodine
- 2g) Strontium phosphite and cesium nitride
- 2h) Carbon dioxide, water, and sulfur dioxide
- 2i) Iron oxide(III) and carbon dioxide
- 2j) Magnesium acetate and hydrogen gas
Explanation:
1. For each of the following, convert the word equation into a formula equation, BUT do not balance!
a) Barium chlorate → Barium chloride + Oxygen
<u>1. Chemical formulas</u>
Barium chlorate:
- It is a salt: an ionic compound.
- Barium has oxidation state +2
- Chlorate is the ion ClO₃⁻
- Swap the oxidation numbers to write the subscripts: 2 goes to ClO₃ and 1 goes to Ba
- Chemical formula Ba(ClO₃)₂
- It is solid: Ba(ClO₃)₂(s)
Barium chloride:
- It is a salt: an ionic compount
- Barium has oxidation state +2
- Chlorine is in oxidation state -1
- Swap the numbers to write the subscripts: 2 goes to Cl and 1 goes to Ba
- BaCl₂
- It is solid BaCl₂(s)
Oxygen:
- It is a diatomic gas molecule
- O₂(g)
<u />
<u>2. Write the unbalanced molecular equation:</u>
- BaClO₃(s) → BaCl₂(s) + O₂(g)
b) Chlorine + Potassium nitride → Nitrogen + Potassium chloride
<u>1. Chemical formulas</u>
Chlorine:
- It is a diatomic gas molecule
- Cl₂(g)
Potassum nitride
- Potassium has oxidation state +1
- Nitrogen is with oxidation state +3
- Swap the oxidation states
- K₃N
- It is solid: K₃N(s)
Nitrogen:
- It is a diatomic gas
- N₂(g)
Potassium chloride
- It is a salt (ionic compound)
- Potassium has oxidation state +1
- Chlorine is in oxidation state -1
- Swap the oxidation numbers
- KCl
- It is solid: KCl(s)
<u>2. Write the unbalanced molecular equation</u>
<u />
- Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)
c) Sodium nitride + Aluminum bromate → Aluminum nitride + Sodium bromate
<u>1. Chemical formulas</u>
Sodium nitride
- It is a salt (ionic compound)
- Sodium has oxidation state +1
- Nitrogen is with oxidation state -3
- Swap the oxidation numbers
- Na₃N
- It is in aqueous solution
- Na₃N (aq)
Aluminum bromate
- Salt
- Aluminum has oxidation state +3
- Bromate is the ion BrO₃⁻
- Swap the oxidation states
- Al(BrO₃)₃ (aq)
Aluminum nitride
- Both Al and N have oxidation state 3, which simply
- AlN(s). It is not soluble in water.
Sodium bromate
<u>2. Write the unbalanced molecular equation</u>
- Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)
<h2>
This is a long answer with more than 5,000 charaters; thus, I have to add the rest of the explanations on a separate file.</h2><h2>
</h2><h2>
The attached file contains the complete answer.</h2>
Answer: The frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is 
.
Explanation:
Given: Wavelength = 546 nm 
= 
The relation between frequency and wavelength is as follows.
where,
= frequency
c = speed of light = 
= wavelength
Substitute the values into above formula as follows.
Thus, we can conclude that the frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is .
