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3 years ago

Calculate the second volumes. 955 L at 58 C and 108 KPa to 76 C and 123 KPa

Chemistry

1 answer:

Dmitriy789 [7]3 years ago

3 0

The second volume : V₂= 884.14 L

<h3>Further explanation </h3>

Given

955 L at 58 C and 108 KPa

76 C and 123 KPa

Required

The second volume

Solution

T₁ = 58 + 273 = 331 K

P₁ = 108 kPa

V₁ = 955 L

P₂ = 123 kPa

T₂ = 76 + 273 = 349

Use combine gas law :

P₁V₁/T₁ = P₂V₂/T₂

Input the value :

108 x 955/331 = 123 x V₂/349

V₂= 884.14 L

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Answer:

Ksp = [ Cu+² ] [ OH-] ²

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Ksp = [ Cu+² ] [ OH-] ²

Ksp [ cu (OH)2 ] = 2.2 × 10-²⁰

|__________|___Cu+² __|_2OH-____|

|Initial concentration(M)|___0__|_0______|

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Ksp = [ Cu+² ] [ OH-] ²

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Solubility of Cu (OH)2 =

$Cu (OH)2 = \frac{1.8 \times {10}^{ - 7} mol \:Cu (OH)2 }{1L} \times \frac{97.546 \: g \: Cu (OH)2}{1 \: mol \: Cu (OH)2} \\ = 1.75428 \times 10 ^{ - 5}$

<h3>Solubility of Cu (OH)2 = 1.75428 × 10 -⁵ g/ L</h3>

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3 years ago

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Answer : Option B) Energy from the environment fuels production.

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Answer:

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PV = nRT

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V = volume (L)

n = number of moles (mol)

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T = temperature (K)

The balanced chemical equation in this question is as follows:

CaC2(s) + 2H2O(l) --> Ca(OH)2(aq) + C2H2(g)

From the equation, 1 mole of CaC2 produces 1 mole of ethylene gas, C2H2.

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