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3 years ago

How do you do unknown area problems on the coordinate plane

1 answer:

4 0

It's not any different from a regular unknown area problem, my friend.

It all depends on the figure, but let's take a square in this example.

You simply count up the units, and multiply length by width.

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Solve the following equation algebraically:

Likurg_2 [28]

Answer:

c. $x = \pm 7$

Step-by-step explanation:

$2x^2 = 98$

$x^2 = 49$

$x = \pm\sqrt{49}$

$x = \pm 7$

4 0

2 years ago

I need help fast pls help

blagie [28]

Answer:

I cannot really see the q

4 0

2 years ago

Does anyone know which one it is ?

hammer [34]

Answer:

The slope of the line is undefined

Step-by-step explanation:

The given line is a vertical line.

The slope of any vertical line is undefined.

Let us see why by using the slope formula:

$m = \frac{y_2-y_1}{x_2-x_1}$

We substitute the coordinates of the points to obtain:

$m = \frac{3 - - 2}{1 - 1} = \frac{5}{0}$

This is not defined.

4 0

2 years ago

O two decimal places, find the value of k that will make the function f(x) continuous everywhere. F of x= 3(x) + k for x less th

enot [183]

Answer:

k ≈ 1.88

Step-by-step explanation:

In order for the function to be continuous, the pieces of the function must have the same value at x=3. That is ...

f(3) = 3(3) +k = k(3^2) -6

15 = 8k . . . . . add 6-k, simplify

k = 15/8 = 1.875 ≈ 1.88

To two decimal places, the value of k that makes f(x) continuous at x=3 is 1.88.

5 0

2 years ago

Confused about this

nikitadnepr [17]

Use a ruler to measure the distance between the two dots and then use the equation to find the actual measurement

8 0

2 years ago