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elena55 [62]
4 years ago
14

How do you do unknown area problems on the coordinate plane

Mathematics
1 answer:
kirill115 [55]4 years ago
4 0
It's not any different from a regular unknown area problem, my friend.

It all depends on the figure, but let's take a square in this example.

You simply count up the units, and multiply length by width.
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If the sides of a triangle have measures 3x + 4, 6x – 1 and 8x + 2, find all possible values of x.
marissa [1.9K]

Answer: x>-4/3

Step-by-step explanation:All sides must be greater of zero:

3x+4>0

3x> -4 Divide with 3

x> -4/3

6x-1>0

6x>1 Divide with 6

x>1/6

8x+2>0

8x> -2 Divide with 8

x> -2/8

x> -1/4

Least of that numbers is -4/3= -1.3333

x> -4/3 is solution

4 0
4 years ago
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3 years ago
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3 years ago
Geometry help please
kotegsom [21]
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3 years ago
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