Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
Answer:
Step-by-step explanation:
ASA because you have the given angles and sides ≅ and the vertical angles are also ≅
2 miles = 3520 yards
FORMULA multiply the length value by 1760
The perimeter of the given circle is 25.1 square cm.
Step-by-step explanation:
- From the given diagram, the radius of the given circle is 4 cm.
- The perimeter of any given circle is calculated by multiplying 2π with the radius. The radius of this circle is 4 cm and it says π = 3.142
- The Perimeter for the given circle = 2π × r = 2 × 3.142 × 4 cm = 6.284 × 4 cm = 25.136 cm. Rounding this off to one decimal 25.136 square cm, the perimeter equals 25.1 square cm.
Answer:
option A is correct answer
divide both sides with 2
hope it helps
