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Savatey [412]
3 years ago
6

A running coach checks on his team's best recorded sprinting times during practice. Drag the runners in order from the greatest

to the least unit rate in meters per second.
Mathematics
1 answer:
horrorfan [7]3 years ago
6 0

Carla

Amir

Carlo

Esther

From greatest to least!

You might be interested in
Math 8: Linear Functions, Part 2
Studentka2010 [4]

Answer:

\boxed{\text{1. y + 5 = -4(x - 3); \qquad 2. y - 8 = x + 1}}

Step-by-step explanation:

Question 1

The point-slope formula for a straight line is

y – y₁ = m(x – x₁)

x₁ = 3; y₁ = -5; m = -4  

Substitute the values

\boxed{\textbf{y + 5 = -4(x - 3)}}

The diagram shows the graph of equation 1 (red) with slope -4 passing through (3,-5).

Question 2

x₁ = -1; y₁ = 8; m = 1  

Substitute the values

\boxed{\textbf{y - 8 = x + 1}}

The diagram shows the graph of equation 2 (green) with slope 1 passing through (-1,8).

3 0
3 years ago
Can somone please help me? I need help with 7 different problems!! and fasttttt
kramer
What problems are they??
8 0
3 years ago
The question is evaluate x÷1.2 for each value of x         x=40.8
Aleks [24]
x:1.2\\\\x=40.8\to40.8:1.2=34

4 0
3 years ago
Evaluate 6 over 3 plus 7 and times 4
jolli1 [7]

Answer:

B 244

Step-by-step explanation:

6^3 +7*4

PEMDAS says exponents first

216 + 7*4

Then multiply and divide

216 +28

Now we add and subtract

244

3 0
3 years ago
Read 2 more answers
(x^(2)-11x+30)/(x^(2)-25)*(x^(2)+6x+5)/(x-5x-6) simplify the rational expression
DanielleElmas [232]
Simplify the following:
((x^2 - 11 x + 30) (x^2 + 6 x + 5))/((x^2 - 25) (x - 5 x - 6))

The factors of 5 that sum to 6 are 5 and 1. So, x^2 + 6 x + 5 = (x + 5) (x + 1):
((x + 5) (x + 1) (x^2 - 11 x + 30))/((x^2 - 25) (x - 5 x - 6))

The factors of 30 that sum to -11 are -5 and -6. So, x^2 - 11 x + 30 = (x - 5) (x - 6):
((x - 5) (x - 6) (x + 5) (x + 1))/((x^2 - 25) (x - 5 x - 6))

x - 5 x = -4 x:
((x - 5) (x - 6) (x + 5) (x + 1))/((x^2 - 25) (-4 x - 6))

Factor -2 out of -4 x - 6:
((x - 5) (x - 6) (x + 5) (x + 1))/(-2 (2 x + 3) (x^2 - 25))

x^2 - 25 = x^2 - 5^2:
((x - 5) (x - 6) (x + 5) (x + 1))/(-2 (x^2 - 5^2) (2 x + 3))

Factor the difference of two squares. x^2 - 5^2 = (x - 5) (x + 5):
((x - 5) (x - 6) (x + 5) (x + 1))/(-2(x - 5) (x + 5) (2 x + 3))

((x - 5) (x - 6) (x + 5) (x + 1))/((x - 5) (x + 5) (-2) (2 x + 3)) = ((x - 5) (x + 5))/((x - 5) (x + 5))×((x - 6) (x + 1))/(-2 (2 x + 3)) = ((x - 6) (x + 1))/(-2 (2 x + 3)):
((x - 6) (x + 1))/(-2 (2 x + 3))

Multiply numerator and denominator of ((x - 6) (x + 1))/(-2 (2 x + 3)) by -1:

Answer: (-(x - 6) (x + 1))/(2 (2 x + 3))
4 0
3 years ago
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