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Ugo [173]
3 years ago
8

Solve the linear inequality −6x+5>−1

Mathematics
1 answer:
Leto [7]3 years ago
7 0
The answer to this question is:

x<1
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Which is an advantage of using a checking account? You can pay only in cash, which can help you avoid splurging. You can pay by
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You can pay in check
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3 years ago
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Consider a melody to be 7 notes from a single piano octave, where 2 of the notes are white key notes and 5 are black key notes.
igor_vitrenko [27]

Answer:

35,829,630 melodies

Step-by-step explanation:

There are 12 half-steps in an octave and therefore 12^7 arrangements of 7 notes if there were no stipulations.

Using complimentary counting, subtract the inadmissible arrangements from 12^7 to get the number of admissible arrangements.

\displaystyle \_\_ \:B_1\_\_ \:B_2\_\_ \:B_3\_\_ \:B_4\_\_ \:B_5\_\_

B_1 can be any note, giving us 12 options. Whatever note we choose, B_2, B_{...} must match it, yielding 12\cdot 1\cdot 1\cdot 1\cdot 1=12. For the remaining two white key notes, W_1 and W_2, we have 11 options for each (they can be anything but the note we chose for the black keys).

There are three possible arrangements of white key groups and black key groups that are inadmissible:

WWBBBBB\\WBBBBBW\\BBBBBWW

White key notes can be different, so a distinct arrangement of them will be considered a distinct melody. With 11 notes to choose from per white key, the number of ways to inadmissibly arrange the white keys is \displaystyle\frac{11\cdot 11}{2!}.

Therefore, the number of admissible arrangements is:

\displaystyle 12^7-3\left(\frac{12\cdot 11\cdot 11}{2!}\right)=\boxed{35,829,630}

6 0
2 years ago
When Mr. Woodward went to his fridge to get the pizza he had bought, his kids have already eaten three-quarters of it. He wanted
dalvyx [7]

Answer:

1/8

Step-by-step explanation:

8 0
3 years ago
35 of of 30 in simplest form
Mariana [72]

Answer:7/6

Step-by-step explanation:

divide both 35 & 30 by 5 since it’s their greatest common factor.

that would get u 7/6

8 0
2 years ago
Mr. Sosa has 35 students in his class. He wishes to place them into 5 groups of equal size for a
Arte-miy333 [17]
35 / 5 = 7

7 students will be assigned to each group.
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3 years ago
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