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monitta
3 years ago
12

What are the possible numbers of positive, negative, and complex zeros of f(x)= -x^6 + x^5 - x^4 + 4x^3 - 12x^2 + 12?

Mathematics
1 answer:
inn [45]3 years ago
6 0
Using Descartes' Rule of Signs:
The signs are: - + - + - +
There are 5 signs changes in this sequence, so there could be either 5, 3, or 1 positive roots.
If we negate the terms with odd numbers (x^5, x^3), we end up with the signs: - - - - - +
Since there is 1 sign change, there can be only 1 negative root.
This means the positive and negative roots can either be 6, 4, or 2.
Since the total number of roots cannot exceed 6, there are either 0, 2, or 4 complex roots.
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Solve equation using square roots (x-1)^2=4
Aneli [31]
X is equal 3. to do this, you do reverse of order of operations. So this means that you would to the 'times 2' first by dividing 4 by 2 to make it 2. then, in the parenthesis, since there is a 'minus 1', therefore you are going to add 1+2 which equals three.  <span />
4 0
3 years ago
(1CQ) Determine whether the series -8/5+32/25-128/125+... is convergent or divergent.
Ivan

Answer:

The series is convergent answer ⇒ (a)

Step-by-step explanation:

* The series is -8/5 + 32/25 + -128/125 + ........

- It is a geometric series with:

- first term a = -8/5 and common ratio r = 32/25 ÷ -8/5 = -4/5

* The difference between the convergent and divergent

  in the geometric series is :

- If the geometric series is given by  sum  = a + a r + a r² + a r³ + ...

* Where a is the first term and r is the common ratio

* If |r| < 1 then the following geometric series converges to a / (1 - r).  

- Where a/1 - r is the sum to infinity

* The proof is:

∵ S = a(1 - r^n)/(1 - r) ⇒ when IrI < 1 and n very large number

∴ r^n approach to zero

∴ S = a(1 - 0)/(1 - r) = a/(1 - r)

∴ S∞ = a/1 - r

* If |r| ≥ 1 then the above geometric series diverges

∵ r = -4/5

∴ IrI = 4/5

∴ IrI < 1

∴ The series is convergent

3 0
3 years ago
Need help please ty (:<br> Find x.
MArishka [77]
<h3>Answer:  x = 18 (choice B)</h3>

===================================

Work Shown:

Through the inscribed angle theorem, we can say that 2 times the inscribed angle gets us the arc that the inscribed angle cuts off.

2*(inscribed angle) = arc measure

2*(2x+2) = 76

4x+4 = 76

4x+4-4 = 76-4 ... subtract 4 from both sides

4x = 72

4x/4 = 72/4 ... divide both sides by 4

x = 18

8 0
4 years ago
Read 2 more answers
Someone please help, i’ll mark brainliest :)
ladessa [460]

Answer:

The first one is:

\left[\begin{array}{ccc}0&7&2\\5&3&1\\4&-1&6\end{array}\right]

The second one is:

\left[\begin{array}{ccc}1&2&6\\8&3&-2\\0&4&5\end{array}\right]

The third one is:

\left[\begin{array}{ccc}3&-2&5\\4&2&0\\-1&6&1\end{array}\right]

Step by Step:

<em>First one:</em>

<em>7+0+2=9</em>

<em>6+1+2=9</em>

<em>6+-1+4=9</em>

<em>4+5+0=9</em>

<em>6+3+0=9</em>

<em>Second one:</em>

<em>6+2+1=9</em>

<em>6+-2+5=9</em>

<em>4+5+0=9</em>

<em>0+8+1=9</em>

<em>1+3+5=9</em>

<em>Third one:</em>

<em>3+-2+5=6</em>

<em>4+2+0=6</em>

<em>-1+6+1=6</em>

<em>5+0+1=6</em>

<em>3+4+-1=6</em>

<em>3+2+1=6</em>

<h2>Hope this helps :)</h2>
6 0
3 years ago
Read 2 more answers
ANSWER FAST I WILL GIVE 10 CHAOS IN POE:
Viefleur [7K]
I think it is c I am not sure tho sorry if it is wrong!
7 0
3 years ago
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