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2 years ago

10

Please answer really fast.

2 answers:

sweet [91]2 years ago

5 0

The answer is A. Use distance formula.

Helen [10]2 years ago

5 0

$distance= \sqrt{(-6-8)^{2}+(5-(-2))^2 }= \sqrt{196+49}= \sqrt{245}$

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A real estate company is interested in the ages of home buyers. They examined the ages of thousands of home buyers and found tha

egoroff_w [7]

Answer:

Between 21 years and 75 years

Step-by-step explanation:

Given that a real estate company is interested in the ages of home buyers. They examined the ages of thousands of home buyers and found that the mean age was 48 years old, with a standard deviation of 9 years.

X the ages of home buyers is N(48, 9)

a) $30\leq x\leq 66\\|x-48|\leq 18\\|x-48|\leq 2\sigma$

Hence using Cheby chev inequality

$P(|x-48|\leq 2\sigma)\geq 1-\frac{1}{2^2} \\=0.75$

b) $25.5\leq x\leq 70.5\\|x-48|\leq 22.5\\|x-48|\leq 1.5\sigma$

$P(|x-48|\leq 1.5\sigma)\geq 1-\frac{1}{1.5^2} \\=0.556$

c) Using normal distribution we have

$P(|x-48|\leq 2\sigma)=0.95$

d) z value is 2.97

Hence x lies between

$(48-9*2.97, 49+9*2.97)\\=(21.27,74.73)$

Between 21 years and 75 years

4 0

3 years ago

Find the volume of the pyramid 10ft 8yd 9yd

Slav-nsk [51]

Answer= 120
Explanation= plugged it into a calculator

3 0

2 years ago

Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).

lutik1710 [3]

Answer:

The arc length is $\dfrac{21}{16}$

Step-by-step explanation:

Given that,

The given curve between the specified points is

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

The points from $(\dfrac{9}{16},1)$ to $(\dfrac{9}{8},2)$

We need to calculate the value of $\dfrac{dx}{dy}$

Using given equation

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

On differentiating w.r.to y

$\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})$

$\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}$

We need to calculate the arc length

Using formula of arc length

$L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}$

Put the value into the formula

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}$

$L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}$

$L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}$

$L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}$

Put the limits

$L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})$

$L=\dfrac{21}{16}$

Hence, The arc length is $\dfrac{21}{16}$

6 0

3 years ago

Solve for − ∣ x − 2 ∣ + 4 ≤ 0

MakcuM [25]

Answer:

x ≥ 6 or x ≤ -2

Step-by-step explanation:

- I x - 2 I + 4 ≤ 0

- I x - 2 I ≤ -4

I x - 2 I ≥ 4

x - 2 ≥ 4 or x - 2 ≤ -4

x ≥ 6 or x ≤ -2

5 0

2 years ago

Can you please give me the answer

ladessa [460]

Answer:

Your answer should be B. x + -1 +- √17

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers