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3 years ago

The star Antares has a mass of 3.08 x 1031 kg. How might this star be classified?

Chemistry

2 answers:

e-lub [12.9K]3 years ago

8 0

Answer:

The correct answer is supergiant.

Explanation:

The largest stars in the universe are known as the supergiant stars. They can be thousands of times larger in comparison to the Sun and exhibits a mass of up to 100 times greater. The supergiants come in an array of temperatures and sizes, however, they are usually categorized as being either blue or red.

The red supergiants exhibit a mass of about 8 times more than the Sun, and are usually old stars, which were once identical in size to the Sun. On the other hand, the blue supergiants are hotter in comparison to the red supergiants, however, are much smaller in size.

MatroZZZ [7]3 years ago

6 0

A red super giant hope that helps

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30 its ASAP!!!! What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 oC and 0.980 atm?

USPshnik [31]

Use the universal gas formula

PV=nRT
where
P=pressure ( 0.980 atm)
V=volume (L)
T=temperature ( 23 ° C = 23+273.15 = 296.15 ° K)
n=number of moles of ideal gas (0.485 mol)
R=universal gas constant = <span>0.08205 L atm / (mol·K)

Substitute values,
Volume, V (in litres)
=nRT/P
=0.485*0.08205*296.15/0.980
= 12.0256 L
= 12.0 L (to three significant figures)

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5 0

3 years ago

How many moles of O2 are needed to react completely with 35.0 mol C2h2

Wittaler [7]

Hey There!:

2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

2 moles C2H2 ----------- 5 moles O2

35.0 moles C2H2 ------- moles O2

moles O2 = 35.0 * 5 / 2

moles O2 = 87.5 moles

hope this helps!

6 0

3 years ago

19. What is sthe mass of 6.02 x 1024 atoms

alekssr [168]

The mass of magnesium in $6.02 \times 10^{24}$ atoms is 240 g.

Answer: Option A

<u>Explanation:</u>

First, we have to convert the atoms to moles of magnesium.

We know that $6.02 \times 10^{24}$ atoms are present in 1 mole of magnesium. So,

$\text { 1 atom }=\frac{1}{6.02 \times 10^{24}} \text { moles }$

$6.02 \times 10^{24} \text { atoms }=\frac{6.02 \times 10^{24}}{6.02 \times 10^{23}} \text { moles }=10 \text { moles }$

Thus,

$Mass of M g= molar mass of M g \times No. of moles of M g$

$\text { Mass of } M g=24 \times 10=240 g$

Thus, 240 g of Magnesium is present in $6.02 \times 10^{24}$ atoms.

4 0

3 years ago

Suppose you are titrating vinegar, which is an acetic acid solution

kotegsom [21]

Answer:

0.373 M

Explanation:

The balanced equation for the reaction is given below:

HC2H3O2 + NaOH —> NaC2H3O2 + H2O

From the balanced equation above, the following were obtained:

Mole ratio of the acid, HC2H3O2 (nA) = 1

Mole ratio of the base, NaOH (nB) = 1

Next, we shall write out the data obtained from the question. This include:

Volume of base, NaOH (Vb) = 32.17 mL

Molarity of base, NaOH (Mb) = 0.116 M

Volume of acid, HC2H3O2 (Va) = 10 mL

Molarity of acid, HC2H3O2 (Ma) =..?

The molarity of the acid solution can be obtained as follow:

MaVa/MbVb = nA/nB

Ma x 10 / 0.116 x 32.17 = 1

Cross multiply

Ma x 10 = 0.116 x 32.17

Divide both side by 10

Ma = (0.116 x 32.17) /10

Ma = 0.373 M

Therefore, the concentration of the acetic acid is 0.373 M.

8 0

3 years ago

Given the following table, which statement is true about atoms A and B?

lisabon 2012 [21]

Answer:

The statement true is A. A and B are isotopes of the same element.

Explanation:

Isotopes correspond to atoms of the same element with different mass numbers (A), that is to say they differ in the amount of neutrons in the nucleus. In the case of compound A it has 10 neutrons, and B has 11.

6 0

3 years ago