All categories

3 years ago

The star Antares has a mass of 3.08 x 1031 kg. How might this star be classified?

Chemistry

2 answers:

e-lub [12.9K]3 years ago

8 0

Answer:

The correct answer is supergiant.

Explanation:

The largest stars in the universe are known as the supergiant stars. They can be thousands of times larger in comparison to the Sun and exhibits a mass of up to 100 times greater. The supergiants come in an array of temperatures and sizes, however, they are usually categorized as being either blue or red.

The red supergiants exhibit a mass of about 8 times more than the Sun, and are usually old stars, which were once identical in size to the Sun. On the other hand, the blue supergiants are hotter in comparison to the red supergiants, however, are much smaller in size.

MatroZZZ [7]3 years ago

6 0

A red super giant hope that helps

You might be interested in

"At constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature." This is -

Lostsunrise [7]

Answer: B

Explanation:

According to Charle's law, at constant pressure the volume of a fixed mass of a ga is directly proportional to its absolute temperature.

At constant pressure, V∝T.

6 0

2 years ago

How many subshells are there in the shell with n = 6?

andre [41]

The number of subshells within a certain shell can be identified using the orbital angular momentum quantum number "l"

"l" is given values from zero till (n-1)
So, for n=6
l is given the following values: 0,1,2,3,4,5
Counting the number of subshells, we will find that the shell with n=6 has 6 subshells

7 0

2 years ago

Depending upon the tip of a dropper pipet there are approximately 20 drops per milliliter of water. the experimental procedure p

Murrr4er [49]

Answer : The volume range in milliliters for the solution is 0.25 - 0.5 mL

Explanation :

We have been given that there are approximately 20 drops per milliliter of water

This information can be used as a conversion factor as $\frac{1mL}{20 drops}$

We are using 5-10 drops of the solution.

Let us calculate milliliters in 5 drops.

$5 drops \times\frac{1 mL}{20 drops} = 0.25 mL$

Similarly, 10 drops would contain

$10 drops \times\frac{1 mL}{20 drops} = 0.5 mL$ solution.

Therefore the volume range in milliliters for the solution is 0.25 - 0.5 mL

8 0

3 years ago

Freon-12 CCl2F2, is prepared from CCl4 by reaction with HF. The other product of this reaction is HCl. Outline the steps needed

LekaFEV [45]

Answer:

percent yield = 40.6 %

Explanation:

The question asks to determine the percent yield, which can be defined as:

percent yield = $\frac{actual yield}{theoretical yield} *100$

where the actual yield is how much product was obtained, in this case 12.5 g of CCl₂F₂, and the theoretical yield is how much product could be obtained with the given reactants theoretically.

So we know already the actual yield, we need to calculate the theoretical yield.

First we need to write the reaction chemical equation:

CCl₄ + HF → CCl₂F₂ + HCl

and balance the equation:

CCl₄ + 2 HF → CCl₂F₂ + 2 HCl

In the equation we can see that for every mol of CCl₄ we should get 1 mol of CCl₂F₂ (molar ratio 1:1). So if we calculate the moles of CCl₄ in the given 39.2 g of CCl₄ we could know how many moles of CCl₂F₂ (assuming HF is in excess).

Moles of CCl₄ = mass CCl₄ / molar mass CCl₄
Molar Mass CCl₄ = 12.011 + 4 * 35.45 = 153.811 g/mol
Moles of CCl₄ = 39.2 g / 153.811 g/mol = 0.2549 moles

From the molar ratio we know:

Moles of CCl₂F₂ = moles of CCl₄ = 0.2549 moles

Now we need to convert these moles into grams to get the theoretical yield of CCl₂F₂ in grams:

mass CCl₂F₂ = moles CCl₂F₂ * molar mass CCl₂F₂
Molar Mass CCl₂F₂ = 12.011 + 2 * 35.45 + 2 * 18.998 = 120.907 g/mol
Mass CCl₂F₂ = 0.2549 moles * 120.907 g/mol = 30.81 g

Theoretical yield CCl₂F₂ = 30.81 g

Percent yield = (12.5 g / 30.81 g) * 100 = 40.6 %

8 0

3 years ago

Who wants to be long distance friends?

Novay_Z [31]

Answer:

(im mostly answering to get points) but im down

Explanation:

6 0

3 years ago

Read 2 more answers