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vladimir2022 [97]
2 years ago
14

What is the general trend for electronegativity

Chemistry
1 answer:
Kruka [31]2 years ago
7 0

Answer:

finna look it up

Explanation:

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Submit your answer for the remaining reagent in Tutorial Assignment #1 Question 9 here, including units. Note: Use e for scienti
djverab [1.8K]
<h3>Answer:</h3>

The mass of excessive water (H₂O) is 40.815 kg

<h3>Explanation:</h3>

The Equation for the reaction is;

Li₂O(s) + H₂O(l) → 2LiOH(s)

From the question;

Mass of water removed is 80.0 kg

Mass of available Li₂O is 65.0 kg

We are required to calculate the mass of excessive reagent.

<h3>Step 1: Calculating the number of moles of water to be removed</h3>

Moles = Mass ÷ Molar mass

Molar mass of water = 18.02 g/mol

Mass of water = 80 kg (but 1000 g = 1kg)

                        = 80,000 g

Therefore;

Moles of water = \frac{80,000g}{18.02 g/mol}

                = 4.44 × 10³ moles

<h3>Step 2: Moles of Li₂O available </h3>

Moles = mass ÷ molar mass

Mass of Li₂O  available = 65.0 kg or 65,000 g

Molar mass Li₂O  = 29.88 g/mol

Moles of Li₂O  = 65,000 g ÷ 29.88 g/mol

          = 2.175 × 10³ moles Li₂O

<h3>Step 3: Mass of excess reagent </h3>

From the equation; Li₂O(s) + H₂O(l) → 2LiOH(s)

1 mole of Li₂O reacts with 1 mole of water to form two moles of LiOH

The ratio of Li₂O to H₂O is 1:1

  • Thus, 2.175 × 10³ moles of Li₂O will react with 2.175 × 10³ moles of water.
  • However, the number of moles of water to be removed is 4.44 × 10³ moles  but only 2.175 × 10³ moles will react with the available Li₂O.
  • This means, Li₂O  is the limiting reactant while water is the excessive reagent.

Therefore:

Moles of excessive water =  4.44 × 10³ moles  - 2.175 × 10³ moles

                                           = 2.265 × 10³ moles

Mass of excessive water = 2.265 × 10³ moles × 18.02 g/mol

                                          = 4.0815 × 10⁴ g or

                                          = 40.815 kg

Thus, the mass of excessive water is 40.815 kg

7 0
3 years ago
How many moles are represented by 3.01x10^23 helium atoms
Alex787 [66]

Answer:

b. 0.50 moles

Explanation:

To solve this problem we use <em>Avogadro's number</em> (6.023x10²³ atoms/mol).

By <u>dividing the number of atoms (or molecules) by that number</u>, we can calculate how many moles they represent.

  • 3.01x10²³ atoms ÷ 6.023x10²³ atoms/mol = 0.50 moles

So the answer is option b. 0.50 moles.

4 0
2 years ago
In the process of eukaryotic pre-mRNA splicing, how is the lariat intermediate formed?
Aleks [24]

Answer:

C

Explanation:

The Eukaryotic pre-mRNA receives a 5' cap and 3'poly(A) tail before Introns are removed and the mRNA is considered ready for translation.

4 0
2 years ago
How is a lithium atom (Li) different from a lithium ion (Li+)?
sdas [7]
<span>Li has fewer electrons than Li+ (protons can't change)
</span>
8 0
3 years ago
Read 2 more answers
A sample of gas has a volume of 1.9L and a temperature of 21 degrees celsius. Heat is applied to the sample, leading to an incre
Mashutka [201]

Answer:

1.94 L

Explanation:

21°C = 21 +273 = 294 K

27°C = 27 + 273 = 300 K

T1/V1 = T2/V2

294 K/1.9 L = 300 K/x L

x = (1.9*300)/294 ≈ 1.94 L

3 0
3 years ago
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