It is OH- (hydroxide ion)
the answer is chlorophyll.
hope this helped. God bless.
Answer is: The molar solubility of ba3(po4)2 is <span>6.00 x 10-39.
</span>Balanced chemical reaction: Ba₃(PO₄)₂(s) → 3Ba²⁺(aq) + 2PO₄³⁻(aq).
s(Ba₃(PO₄)₂) = 8.89·10⁻⁹ M.
[Ba²⁺] = 3s(Ba₃(PO₄)₂) = 3s.
[PO₄³⁻] = 2s.
Ksp = [Ba²⁺]³ · [PO₄³⁻]².
Ksp = (3s)³ · (2s)².
Ksp = 108s⁵.
Ksp = 108·(8.89·10⁻⁹ M)⁵.
Ksp = 108 · 5.55·10⁻⁴¹ = 6·10⁻³⁹.
<span>The answer is No, it is
not possible that the reverse reaction will occur at ordinary conditions. This
is because the entropy of the KCl and the O2 are much largely negative than
that of the KClO3. The entropy component of the Gibbs free energy assures that
the Gibbs free energy for the reverse reaction is positive (Positive Gibbs
means nonspontaneous reaction). </span>
Answer:
As, the temperature decreased from 40.0 °C to 0.0 °C an amount will be recrystallized and precipitated as solid crystals in the water (51.0 g - 14.0 g = 37.0 g) and 14.0 g will be dissolved in water.
Explanation:
- Firstly, we must mention that:
The solubility of KNO₃ per 100.0 g of water at 40.0 °C = 63.0 g.
The solubility of KNO₃ per 100.0 g of water at 0.0 °C = 14.0 g.
- So, at 40.0 °C, 51.0 g of KNO₃ will be completely dissolved in water.
- <em>As, the temperature decreased from 40.0 °C to 0.0 °C an amount will be recrystallized and precipitated as solid crystals in the water (51.0 g - 14.0 g = 37.0 g) and 14.0 g will be dissolved in water.</em>
