Answer:
1kg= 1000 grams hope it helps
Answer:
Wouldn't the Earth's atmosphere be moving too fast that it eventually breaks out?
Explanation:
Do NOT trust me.
Answer:
52.8 g of O2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
4Al + 3O2 —> 2Al2O3
From the balanced equation above,
4 moles of Al reacted with 3 moles of O2 to produce 2 moles of Al2O3
Next, we shall determine the number of mole of O2 needed to react with 2.2 moles of Al. This can be obtained as follow:
From the balanced equation above,
4 moles of Al reacted with 3 moles of O2.
Therefore, 2.2 moles of Al will react with = (2.2 × 3)/4 = 1.65 moles of O2.
Thus, 1.65 moles of O2 is needed for the reaction.
Finally, we shall determine the mass of O2 needed as shown below:
Mole of O2 = 1.65 moles
Molar mass of O2 = 2 × 16= 32 g/mol
Mass of O2 =?
Mole = mass/Molar mass
1.65 = mass of O2 /32
Cross multiply
Mass of O2 = 1.65 × 32
Mass of O2 = 52.8 g
Therefore, 52.8 g of O2 is needed for the reaction.
B Phytoplankton - Zooplankton - Arctic cod - Ringed sal
Explanation:
The food chain that describes the path through which energy takes will be phytoplankton-zooplankton-Arctic cod-Ringed sal. Energy moves in the ecosystem from producers to primary consumers then secondary and tertiary consumers.
- Autotrophs are those organisms that manufacture their own food. The use chemical substances from the environment to produce their nourishment which serves as the source of energy for the whole ecosystem too.
- Autotrophs are the producers in any ecosystem and they are usually the plants.
- The phytoplankton is an autotroph.
- Next up are the primary consumers that takes up the produced food by the autotrophs for their own nourishment. In the chain above, the Zooplankton is the primary consumer.
- The secondary consumer that feeds on the zooplankton is the Arctic cod.
- The tertiary consumer is the Ringed Sal which feeds directly on the Arctic cod.
Learn more:
food chain brainly.com/question/2497487
#learnwithBrainly
<h2>
Answer: 8.69 × 10⁻¹ Hz
</h2>
<h3>
Explanation:
</h3>
Frequency = Speed of Light ÷ Wavelength
= (2.99 × 10⁸ m/s) ÷ (3.44 × 10⁻⁸ m)
= 8.69 × 10⁻¹ Hz
The frequency of a light of wavelength 34.4 nm is 8.69 × 10⁻¹ Hz.
<u>Notes:</u>
Hz ≡ /s
1 m = 10⁹ nm
