60+68=128
128/2=64
so the answer is 64
I hope this helped
Answer:
The correct answer is 0.52 moles.
Explanation:
Based on the given question, 37 grams of magnesium reacts with 38 grams of HCl to produce MgCl2 or magnesium chloride. The reaction is:
Mg (s) + 2HCl (aq) ⇒ MgCl2 (aq) + H2 (g)
There is a need to find the theoretical yield in moles of MgCl2. The formula for calculating the no. or moles is mass/molar mass. Therefore, moles of magnesium is 37/24 = 1.54 and moles of HCl will be 38/36.5 = 1.04.
From the reaction it is clear that one mole of magnesium reacts with two moles of HCl, as lesser quantity of HCl is present in the given case, therefore, HCl will be the limiting reagent.
Now theoretical moles of magnesium chloride will be,
= moles of HCl / 2
= 1.04 / 2
= 0.52 moles
The a is 5 your welcome dude
Answer: The volume in the balloon at the higher altitude is 260 L
Explanation:
The combined gas equation is,
where,
= initial pressure of gas = 760 torr
= final pressure of gas = 511 torr
= initial volume of gas = 233 L
= final volume of gas = ?
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:
The volume in the balloon at the higher altitude is 260 L
Reaction between mercury (ii) sulfide with Calcium oxide is as shown;
4 HgS +4 CaO = 4 Hg + 3 CaS + CaSO4
The molar mass of HgS is 232.66 g/mol
The number of moles = 31.28/232.66
= 0.1344 moles
The mole ratio of HgS : CaO is 1: 1
Therefore, the number of moles of Calcium oxide is 0.1344 moles
1 mole of CaO Contains 56 g/mol
Thus, the mass of CaO is 56 g/mol
= 0.1344 moles × 56 g/mol
= 7.5264 g
