Answer:
the three consecutive odd integers are 9, 11, and 13.
Step-by-step explanation:
Let's say that the first odd integer is x. The second consecutive odd integer would have to be x+2. (It would not be x+1 because that would result in an even integer. The sum of any two odd numbers is even.) The third consecutive odd integer would be (x+2) +2 or x+4.
The sum of the first, twice the second, and three times the third can be written as:
x+2(x+2)+3(x+4)
This equals 70. We can now distribute and solve for x:
x+2(x+2)+3(x+4)=70
x+2x+4+3x+12=70(distribute)
6x+16=70(combine like terms)
6x=54(subtract 16 from both sides)
x=9(divide by 9)
Thus, the three consecutive odd integers are 9, 11, and 13
hope this helps :)
Answer:6561
Step-by-step explanation: Negative 3 to the power of two is 9, and 9 to the power of 4 is 6561
9b)
Numerator = 1,2,4,8,16 = 2^0, 2^1, 2^2, 2^3, 2^4
Multiples of 2.
If a numerator = x, the next numerator = 2x
1/1,2/(1+2),4/(3+4)
If a denominator = y, the next denominator = y+2x
2x/(2x+y)
9c)
1, 2, 4, 8, 16 = 2^(n-1)
2, 4, 8, 16, 32 = 2^n
1, 3, 7, 15, 31 = 2-1, 4-1, 8-1, 16-1, 32-1 = 2^n - 1
2^(n-1) / ( 2^n - 1 )
Answer:
Step-by-step explanation:
30 = 6*5
48= 6*8
30 + 48 = 6*5 + 6*8
= 6*(5+8)
= 6*13 = 78
