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3 years ago

How to find the rate of something lol

2 answers:

7 0

Rate =distance/time
:)
it's the famous d=r*t (distance is rate multiply by time)
therefore, changing the way of expressing the equation d/t =r you can use it to find r

White raven [17]3 years ago

6 0

Distance-time maybe : ( & :)

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A line has a slope of \large \frac{5}{3}. Which of the following points could this line pass through?

kiruha [24]

Answer:well I will tell if you tell me the answer for my question

Step-by-step explanation:

6 0

3 years ago

How do I find the values of these

skad [1K]

Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"

now using proportions $\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{JK}{18}=\cfrac{12}{12+10}$

solve for JK

$\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{12}{12+10}=\cfrac{9}{9+KG}\implies 12(9+KG)=(22)9
\\\\\\
108+9KG=198$

solve for KG

the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or $\bf \cfrac{12}{12+10}$

3 0

3 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

$g(y) = \frac{y-5}{y^2-3y+15}$

According to the quotient rule:

$d(\frac{f(y)}{h(y)}) = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}$

Applying the quotient rule:

$g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}$

The values for which g'(y) are zero are the critical points:

$g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10$

The critical values are y = 0 and y = 10.

5 0

3 years ago

Use calculator to find the values of the following,correct to 3decimal places: 1. Cot 61,4

g100num [7]

No such thing as cot (61,4). I think you meant to say cot (61.4°). See the difference?

So, cot (61.4°) is approximately -0.139844.

Rounded to 3 decimal places we get -0.140.

6 0

3 years ago

11. Which of the following is a graph of exponential decay? Please help very urgent!!!

Anestetic [448]

Answer:

I believe it's the 3rd answer

8 0

3 years ago