Answer:
I’m not sure :/
Step-by-step explanation:
Complete question :
Standardized tests: In a particular year, the mean score on the ACT test was 19.3 and the standard deviation was 5.3. The mean score on the SAT mathematics test was 532 and the standard deviation was 128. The distributions of both scores were approximately bell-shaped. Round the answers to at least two decimal places. Part: 0/4 Part 1 of 4 (a) Find the z-score for an ACT score of 26. The Z-score for an ACT score of 26 is
Answer:
1.26
Step-by-step explanation:
Given that:
For ACT:
Mean score, m = 19.3
Standard deviation, s = 5.3
Zscore for ACT score of 26;
Using the Zscore formula :
(x - mean) / standard deviation
x = 26
Zscore :
(26 - 19.3) / 5.3
= 6.7 / 5.3
= 1.2641509
= 1.26
<h2>
Explanation:</h2>
Let's use a trial and improvement method to find this solution.
Step 1. Let's choose x = 8.5
Substituting into the equation:
Step 2. Let's choose x = 8.4
Substituting into the equation:
Step 3. Let's choose x = 8.3
Substituting into the equation:
Since the sign of the equation changes from positive to negative when evaluating from 8.4 to 8.3, then x = 8.3 seems to be a reasonable value. Finally, the solution to 1 decimal place is:
Answer:
sin(x) = -sqrt2/2
tan(x) = -1
Step-by-step explanation:
Because it is between 270 and 360, sin is negative, so it is -sqrt2/2.
tan(x) is sin(x)/cos(x), so it is just -1.
Answer:
ok so the answer to the first is 23. And how you get that is take 1 +7 and add them next you subtract 30 - 7 and get 23.
Step-by-step explanation:
The answer to 2 is 32. And how you get that is you can split 96 into 3 groops and when you do you will get 32 hope this helps.
