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11Alexandr11 [23.1K]

2 years ago

11

What is the 10th term of the geometric sequence 1/256,1/128,1/64,1/1

1 answer:

chubhunter [2.5K]2 years ago

4 0

Answer:

2

Step-by-step explanation:

you multiply each term by 2

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Dylan has a square piece of metal that measures 10 inches on each side. he cuts the metal along the diagonal, forming two right

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You need to use the Pythagorean theory. a² + b² = c². So you would end up with 10²+10²=c². So, 10²=100, therefore you would end up with 200=c². In order to find the length of the hypotenuse, you need to find C. To do this, you need to undo the square and find the square root of 200 and C. So, you would get √200=√c² which would equal 14.1 inches. Then, if needed to check the answer, plug the 10,10,and 14.1 back into the a²+b²=c² and it should make the statement true.

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Find the value of x (3x-9) (x + 7)

laila [671]

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Step-by-step explanation:

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3 years ago

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3 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago