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azamat
2 years ago
10

How many times does 88 go in to 11

Mathematics
2 answers:
storchak [24]2 years ago
7 0

\frac{11]{88}=\frac{11}{11*8}

When we can cancel out the 11s, we are left with:

\frac{1}{8}

or 0.125

bazaltina [42]2 years ago
7 0
0.125 that is the answer
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For carolina's birthday her mom took her and her friends to a water park.Carolina mom paid 42.50 for 5 students tickets. What wa
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Answer:

8.5 for each student ticket

Step-by-step explanation:

Simply divide the total cost 42.5 by the amount of students 5 to get your answer.

42.5 / 5 = 8.5

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Kate needs 3 pieces of ribbon. She needs 2 pieces that are each 8.5 inches long and another piece that is 7.75 inches long. She
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Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0
3 years ago
the tables show the typical number of minutes spent exercising each week for a group of fourth-grade students and a group of sev
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3 years ago
Hello please help me with this I need an answer immediately thank you so much see image
hodyreva [135]

For this case, we know that:

PA = PB

Then, by Pythagorean theorem (right triangle on the right) we have:

CP ^ 2 = CB ^ 2-PB ^ 2

So, again using the Pythagorean theorem (right triangle on the left) we have:

CA ^ 2 = CP ^ 2 + PB ^ 2

Substituting values:

CA ^ 2 = (CB ^ 2-PB ^ 2) + PB ^ 2

Rewriting:

CA ^ 2 = CB ^ 2

CA = CB

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Answer:

The value of CA is given by:

CA = 15

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3 years ago
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