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4 years ago

The density of ocean water increases when it

2 answers:

5 0

The correct answer is (b.) gets colder. The density of the ocean water increases when the water gets colder. Therefore, it is already concluded that the density of the water and its temperature is indirectly proportional since as the density increases, the temperature decreases.

ANEK [815]4 years ago

4 0

Answer: Option (b) is the correct answer.

Explanation:

Density means the degree of compactness, that is, when particles of an object or substance are closer to each other then it is said that density of object is high.

Therefore, when ocean water gets colder then particles of water will gain potential energy and thus they will come closer to each other. Hence, there will be increase in density of ocean water when it gets colder.

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You attach a 3.10 kg weight to a horizontal spring that is fixed at one end. You pull the weight until the spring is stretched b

dolphi86 [110]

Answer:

0.785 m/s

Explanation:

Hi!

To solve this problem we will use the equation of motion of the harmonic oscillator, <em>i.e.</em>

$x(t) = A cos(\omega t )+B sin(\omega t)$ - (1)

$\frac{dx}{dt}(t) = \omega (B cos(\omega t )- A sin(\omega t)$ - (1)

The problem say us that the spring is released from rest when the spring is stretched by 0.100 m, this condition is given as:

$x(0) = 0.100$

$\frac{dx}{dt}(0) = 0$

Since cos(0)=1 and sin(0) = 0:

$x(0)=A$

$\frac{dx}{dt}(0) = -B\omega$

We get

$A =0.100\\B = 0$

Now it say that after 0.4s the weigth reaches zero speed. This will happen when the sping shrinks by 0.100. This condition is written as:

$x(0.4) = - 0.100$

Since

$x(t) = 0.100 cos(\omega t)\\ -0.100=x(0.4)=0.100cos(\omega 0.4)$

This is the same as:

$-1 = cos(0.4\omega)$

We know that cosine equals to -1 when its argument is equal to:

(2n+1)π

With n an integer

The first time should happen when n=0

Therefore:

π = 0.4ω

ω = π/0.4 -- (2)

Now, the maximum speed will be reached when the potential energy is zero, <em>i.e. </em>when the sping is not stretched, that is when x = 0

With this info we will know at what time it happens:

$0 = x(t) = 0.100cos(\omega t)$

The first time that the cosine is equal to zero is when its argument is equal to π/2

$t_{maxV}=\pi /(2\omega)$

And the velocity at that time is:

$\frac{dx}{dt}(t_{maxV} ) =- 0.100\omega sin(\omega t_{maxV})\\\frac{dx}{dt}(t_{maxV} ) =- 0.100\omega sin(\pi/2)\\$

But sin(π/2) = 1.

Therefore, using eq(2):

$\frac{dx}{dt}(t_{maxV} ) = 0.100*\omega = 0.100\frac{\pi}{0.400} = \pi/4$

And so:

$V_{max} = \pi / 4 =0.785$

6 0

3 years ago

Which of the following statements is TRUE?

KIM [24]

Hello there!

<span>Which of the following statements is TRUE?

Correct answer: </span>Light waves are electromagnetic waves and sound waves are mechanical waves.

5 0

4 years ago

Read 2 more answers

How does the kinetic energy of an object relate to its mass and velocity?

Setler [38]

The kinetic energy of an object is directly proportional to its mass, and to the square of its velocity.

5 0

3 years ago

A ball is shot straight up into the air from the ground with initial velocity of 44ft/sec44ft/sec. assuming that the air resista

solniwko [45]

Convert the given in SI units.

(44 ft/sec)(1 m/ 3.28 ft) = 13.41 m/sec

The distance traveled and the initial velocity can be related through the equation,

d = (Vf)² - (Vi)²/ 2a

where d is the distance, Vf is the final velocity, Vi is the initial velocity, a is the acceleration due to gravity. Substituting the known values from the given above,

d = ((0 m/s)² - (13.41 m/s)²)/ 2(-9.8 m/s²)

The value of d from the equation,

d = 9.17 meters

Convert this to feet,

d = (9.17 m)(3.28 ft / 1 m) = 30 ft

Answer: 30 ft

3 0

3 years ago

How much time will it take for a truck to travel 20 meters if it is traveling at 4 m/s?

ss7ja [257]

Answer:

<h2>The answer is 5 s</h2>

Explanation:

The time taken can be found by using the formula

$t = \frac{d}{v} \\$