2. 0 mc charge in an external field of 20n/c, north (direction) will experience a force of 0.4 newtons, the direction of the force is north
Force in an electric field = charge * electric field
given
charge = 2*
C
electric field = 20 N/C
Force in an electric field = 2*
* 20
= 0.04 N
since , external field is in north direction then the force must be in north direction because the direction of an electric field at a point is the same as the direction of the electric force acting on a positive test charge
hence, 2. 0 mc charge in an external field of 20n/c, north (direction) will experience a force of 0.4 newtons, the direction of the force is north
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Answer:
It's is c coz the weight is equal to the normal force
Answer:
Explanation:
The number of neutrons is 127 and the number of protons will be equal to number of electrons. It has 83 protons and a magic number of 127 neutrons. Bi 210 is radioactive isotope of bismuth.
The region a represents the distance of the electron from the nucleus.
According to the wave mechanical model of the atom, the probability of finding an electron within a given volume element (representing the atom) is the square of the wave function psi.
Since a is the region in space where there is the greatest probability of finding the electron in the atom, it follows that distance of the electron form the atom is always a.
Learn more about the wave mechanical model: brainly.com/question/1382157