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netineya [11]
2 years ago
10

Which term best describes a severe weather event characterized by heavy snowfall, strong winds, and reduced visibility?

Physics
1 answer:
Margaret [11]2 years ago
4 0

Answer:

OC. blizzard

Explanation:

In the United States, the National Weather Service defines a blizzard as a severe snow storm characterized by strong winds causing blowing snow that results in low visibilities. ... A severe blizzard has winds over 72 km/h (45 mph), near zero visibility, and temperatures of −12 °C (10 °F) or lower.

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Bicycle in its writers have combined a mass of 80 kg in a speed of 6.0 meters per Second what is the magnitude of the average fo
erik [133]

Answer:

F = 120 N

Explanation:

Force x distance = energy

The bike has energy 1/2 . 80 . 6^2   = 1440 J

You are looking at an example of not reading the question properly.

Impulse = Force . time  = change in momentum

F . 4  = 80 .6

F = 120 N

7 0
3 years ago
The spring to launch a pinball in a pinball machine is compressed 25 cm and has a spring constant of 140 N/m.
mote1985 [20]

Answer:

I think it is 5.6. This is my answer

8 0
3 years ago
A projectile is launched at ground level with an initial speed of 54.5 m/s at an angle of 35.0° above the horizontal. It strikes
Alchen [17]
<h2>Answer: x=125m, y=48.308m</h2>

Explanation:

This situation is a good example of the projectile motion or parabolic motion, in which we have two components: x-component and y-component. Being their main equations to find the position as follows:

x-component:

x=V_{o}cos\theta t   (1)

Where:

V_{o}=54.5m/s is the projectile's initial speed

\theta=35\° is the angle

t=2.80s is the time since the projectile is launched until it strikes the target

x  is the final horizontal position of the projectile (the value we want to find)

y-component:

y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}   (2)

Where:

y_{o}=0  is the initial height of the projectile (we are told it  was launched at ground level)

y  is the final height of the projectile (the value we want to find)

g=9.8m/s^{2}  is the acceleration due gravity

Having this clear, let's begin with x (1):

x=(54.5m/s)cos(35\°)(2.8s)   (3)

x=125m   (4)  This is the horizontal final position of the projectile

For y (2):

y=0+(54.5m/s)sin(35\°)(2.8s)-\frac{(9.8m/s^{2})(2.8s)^{2}}{2}   (5)

y=48.308m   (6)  This is the vertical final position of the projectile

4 0
3 years ago
When an oxygen atom forms an ion, it gains two electrons. What is the electrical charge of the oxygen ion?
Mashutka [201]
-2. This is because it is gaining electrons. Electrons are negative. Therefore it is a negative charge.
6 0
3 years ago
Water ice has a density of 0.91 g/cm2, so it will float in liquid water. Imagine you have a cube of ice, 10 cm on a side. a. Wha
Reptile [31]

Answer:

(i) W = 8.918 N

(ii) V = 9.1 \times 10^{-4} m^3

(iii) d = 9.1 cm

Explanation:

Part a)

As we know that weight of cube is given as

W = mg

W = \rho V g

here we know that

\rho = 0.91 g/cm^3

Volume = L^3

Volume = 10^3 = 1000 cm^3

now the mass of the ice cube is given as

m = 0.91 \times 1000 = 910 g

now weight is given as

W = 0.910 \times 9.8 = 8.918 N

Part b)

Weight of the liquid displaced must be equal to weight of the ice cube

Because as we know that force of buoyancy = weight of the of the liquid displaced

W_{displaced} = 8.918 N

So here volume displaced is given as

\rho_{water}Vg = 8.918

1000(V)9.8 = 8.918

V = 9.1 \times 10^{-4} m^3

Part c)

Let the cube is submerged by distance "d" inside water

So here displaced water weight is given as

W = \rho_{water} (L^2 d) g

8.918 = 1000(0.10^2 \times d) 9.8

d = 0.091 m

so it is submerged by d = 9.1 cm inside water

4 0
3 years ago
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